Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
Answer:
○ C. The lines are perpendicular.
Step-by-step explanation:
In order for equations to be perpendicular, their <em>rate of changes</em> [<em>slopes</em>] must be OPPOSITE <em>MULTIPLICATIVE</em><em> </em><em>INVERSES</em>, which in this case is so:
− to +}
> OPPOSITE
+ to −}
MULTIPLICATIVE INVERSE [RECIPROCAL]
I am joyous to assist you at any time.
Answer:
13
Step-by-step explanation:
The mean is the average of the data points.
(14 + 17 + 8 + 19 + 7) ÷ 5 = 65 ÷ 5 = 13
Answer:
100
Step-by-step explanation:
