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andreev551 [17]
3 years ago
7

HELP FAST PLEASE I'LL MARK YOU BRAINLIEST What is the slope of a line perpendicular to the line whose equation is x+2y=14. Fully

reduce your answer.
Mathematics
1 answer:
sashaice [31]3 years ago
7 0
Turn it into slope-intercept form.
2y = -x + 14
y = -x/2 + 7
The slope is -1/2.
Perpendicular lines have slopes that are opposite reciprocal, so the slope of the perpendicular line is 2.
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What is the distance between the solutions to the quadratic<br> equation x2 – 7x + 10 = 28
Kryger [21]

Answer:

11

Step-by-step explanation:

Given

x² - 7x + 10 = 28 ( subtract 28 from both sides )

x² - 7x - 18 = 0 ← in standard form

(x - 9)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 9 = 0 ⇒ x = 9

x + 2 = 0 ⇒ x = - 2

The distance between the solutions is

| 9 - (- 2) | = | 11  = 11 units

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

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3 years ago
Air Force One can travel 630 miles per hour. Let x be the number of hours traveled. The function that gives the distance y in mi
4vir4ik [10]
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