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Alja [10]
3 years ago
10

Write an equation where a number is added to a variable, and a solution is -8.

Mathematics
1 answer:
IRISSAK [1]3 years ago
3 0

Answer:

heres a very simple one: x-18= -8 for x=10

Step-by-step explanation:

it just very simple, if you don't have any other choice.

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Sketch a graph of the following inequality and the choose the correct description of the graph: x + y - 5 ≥ 0
maxonik [38]

Answer:

Slope -1, y intercept +5.

Bold line, shaded above

Step-by-step explanation:

x + y - 5 ≥ 0

y ≥ -x + 5

3 0
3 years ago
The sum of two numbers is 43. The larger number is 21 more than the smaller number. What are the numbers?
german

Answer:

The numbers are 11 and 32.  Add to get a sum of 43, and subtract to get a difference of 21.  

Step-by-step explanation:

5 0
3 years ago
How do you solve this -6 ÷[-3/4]=?
sergij07 [2.7K]

The rule to use: when dividing fractions, invert and multiply.

-6 ÷ -(3/4) equals -6 * -(4/3) which equals 24 / 3 which equals

8


7 0
3 years ago
Read 2 more answers
Please find the missing side of this triangle
Strike441 [17]
The answer is 15.01

First you need to find the other angle of the triangle so you do 90+25 which gives you 115 and subtract that by 180 because all angles of a triangle add up to 180. That gives you 65 then you will use TAN(65) and get 2.144506920509559 which you will then multiple by 7 to get 15.01154844356691 which you then round to get 15.01!
7 0
3 years ago
3. Here is a diagram of a softball field:
Crank

a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.

b. The area of the outfield is about 39,584 sq. ft..

<h3>What is the Perimeter of a Quarter Circle?</h3>

Perimeter of circle = 2πr

Perimeter of a quarter circle = 2r + 1/4(2πr).

a. The length of the fence around the field = perimeter of the quarter circle fence

= 2r + 1/4(2πr).

r = 250 ft

Plug in the value

The length of the fence around the field = 2(250) + 1/4(2 × π × 250)

= 892.7 ft.

b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)

= 1/4(πR²) - πr²

R = radius of the full field = 250 ft

r = radius of the infield = 110/2 = 55 ft

Plug in the values

Size of the outfield = 1/4(π × 250²) - π × 55²

= 49,087 - 9,503

= 39,584 sq. ft.

Learn more about perimeter of quarter circle on:

brainly.com/question/15976233

4 0
2 years ago
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