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2 years ago

6

In grade 9 high school to get an honor roll do they look at your midterm marks or do they look at your final marks. I have two s

emesters and live in Canada.

1 answer:

BartSMP [9]2 years ago

5 0

Answer:

Tortileni

Step-by-step explanation:

You might be interested in

Factor the trinomial by grouping.<br> 9x^3 - 3x^2 -30x

katen-ka-za [31]

Answer:

3x(3x+5)(x-2)

Step-by-step explanation:

$9x^3-3x^2-30x= \\\\3x(3x^2-x-10)= \\\\3x(3x^2+5x-6x-10)= \\\\3x(x(3x+5)-2(3x+5))= \\\\3x(3x+5)(x-2)$

Hope this helps!

4 0

3 years ago

What is the solution of the system? Use the elimination method.

Yuki888 [10]

I got D.There is no solution

7 0

3 years ago

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0

3 years ago

CAN ANYONE HELP ME PLZ WIHT JUST 4QUESTIONS

Makovka662 [10]

Yeah sure! Just make sure to post them haha :)

6 0

2 years ago

Identify the solutions to the quadratic equation 6x^2+x-1=0

tigry1 [53]

Answer:

1/3 and -1/2

Step-by-step explanation:

You can use the factoring method to identify the solutions of x

6x^2+x-1

2 numbers have to multiply to 6 and subtract to 1 because x is the same as 1x

So, you get 3x and 2x

since you know that -1x1 is -1 you will get

(3x-1)(2x+1)=0

Now, since (3x-1) and (2x+1) multiply to get 0, if either (3x-1) or (2x+1) is 0 the statement will be valid

3(1/3)-1=0

2(-1/2)+1=0

So, your answers are 1/3 and -1/2

5 0

1 year ago