Ok so from experience on this site
3x2=3x^2
people don't know how to put exponents
3x^2-y^3-y^3-z
simplify first
3x^2-2y^3-z
x=3
y=-2
z=-5
3(3^2)-2(-2)^3-(-5)
3(9)-2(-8)+5
27+16+5
48
Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle:
bh =
⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
⋅4⋅5 =
⋅20 = 10
Our area is 10 square units.
Hope that helps :)
Answer:the answer will be 70
Step-by-step explanation:5 times 14