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snow_lady [41]
3 years ago
11

Elijah spends 5 hours each week working out in a pool. This is twice the

Mathematics
2 answers:
Schach [20]3 years ago
4 0

Answer: he spends 2.5 hours in the weight room each week.

Step-by-step explanation: 2.5 multiplied by 2 (which is the twice amount of time spent working out in the pool) is 5.

So the answer is 2.5

forsale [732]3 years ago
3 0

Answer:the answer will be 70

Step-by-step explanation:5 times 14

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Would Anyone Help Me With These Math Questions Thank You Very Much.
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1) I'm not sure what an open operation is.
2) D
3) No
4) Yes
5) D
6) hmm
7) there doesn't seem to be a 6 or 7
8) C
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3 years ago
Find the sum of x-1 and 6x-8
amm1812

Answer:

7x-9

Step-by-step explanation:

4 0
2 years ago
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What is the ratio of surface area to volume for a sphere with the following
Aneli [31]

The answer would be A Im Sure If not I apologize

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Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]

The left and right endpoints of the i-th subinterval, respectively, are

\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8

r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8

for 1\le i\le4, and the respective midpoints are

m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8

  • Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}

  • Midpoint rule

We approximate the area for each subinterval by

M_i=f(m_i)(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}

  • Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial p_i(x), where

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It so happens that the integral of p_i(x) reduces nicely to the form you're probably more familiar with,

S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))

Then the integral is approximately

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0
3 years ago
A piece of a chain's length and weight are in proportion. If 320 cm of chain weighs 8 kg, then
Dafna11 [192]

Answer:

B. 80 cm of chain weighs 2 kg.

Step-by-step explanation:

In order to choose the correct answer, we need to define the comparative relation between the length and weight of the chain. We will do this by performing the simple operation of division.

It is easier to divide the larger number by the smaller and that is what we will show here (although <em>you can do as you wish and still get the same result</em> - it's math!):

320 ÷ 8 = 40

The result we got is 40. This means that <u>the length of the chain is equal to the value of forty of its weights!</u> And this will be the operation we will perform in order to determine the right answer:

A) Does 2 (kg) multiplied by 40 equal 40 (cm)? No, therefore, it is incorrect.

B) Does 2 (kg) multiplied by 40 equal 80 (cm)? <u>Yes, this answer is correct!</u>

Just in case, we will perform this action with the rest of the possible choices:

C) 4 kg × 40 = 160 and NOT 80 cm.

D) 2 kg × 40 = 80 and NOT 160 cm.

5 0
2 years ago
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