Question

Select the correct answer from each drop-down menu.

Answer 1

Answer:

The length of side AC is 5 units.

The areas of triangle ABC is 10 square units.

Step-by-step explanation:

From point A (1,3) to point C (1,-2) is 5 units

To check this:

3 - (-2) = 3 + 2 =5

We're subtracting since the point went down (from positive 3 to negative 2)

Now for the area:

Area formula for a triangle: $\frac{1}{2}$bh = $\frac{1}{2}$⋅b⋅h

We already found the height (length) : 5

The base is from point C (1,-2) to point B (5,-2), which is 4 units

To check this:

5 - 1 = 4

Now that we have found the base and height, Let's solve:

$\frac{1}{2}$⋅4⋅5 = $\frac{1}{2}$⋅20 = 10

Our area is 10 square units.

Hope that helps :)