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melamori03 [73]
3 years ago
6

what are the coordinates of a point on the directed line segment from (5,9) to (8,-6) that partitions the segment into a ratio o

f 3 to 2
Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

the answer is 15 i think yadayadayada

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I need help ASAP pleaseee helppp I’ll maker brainliest:((<br> It’s number 2
siniylev [52]

Answer:

J

Step-by-step explanation:

When finding the distance between the two points you use the formula

d(distance)= square root of ( x2-x1)^2+(y2-y1)^2. So since you have the two points you just plug them into the formula to get

square root of (5-(-3))^2+(2-(-5))^2 and if you put that in a calculator you get 10.63014581. Then you just round to the nearest tenth and get the final answer of 10.6 (J)

5 0
3 years ago
Use the unit circle to find the value of tan (225 degrees
BARSIC [14]

if you don't have a Unit Circle, this is a good time to get one, you'd need it, you can find many online.

Check the picture below.

3 0
3 years ago
Read 2 more answers
16. Find the values of x and y.<br> (2y + 5)<br> (5r - 17)<br> (3r - 11)
Alinara [238K]
(5x - 17) + (3x - 11)= 180 [ Linear Pair ]
= 8x - 28= 180
= 8x= 208
= x = 208/8
= x = 26

3x-11
= 3*26 - 11
=67

Now, we have:
(2y+5)+90+(3x-11)=180 [Linear Pair]

Substituting (3x-11),
(2y+5) + 90 + 67= 180
= (2y+5)+157= 180
= 2y + 162= 180
= 2y= 18
=y = 18/2
=y= 9

Therefore, x= 26, and y= 9

Please hit the ‘Thanks’ if this helped

Have a great day.
3 0
3 years ago
Find the slope (2/10,-3/2)(3/5,1/2)
maksim [4K]
Slope is equal to the change in y over the change in x,<span> or 'rise over run'.
</span><span>m=change  in  y/change  in  x

</span>The change in x is equal to the difference in x-coordinates (also called run), and the change in y is equal to the difference in y-coordinates (also called rise<span>).
</span><span>m=y^2−y^1/x^2−x^1

</span>Substitute in the values of x and y into the equation to find the slope<span>.
</span><span>m= 1/2 −(− 3/2 )/ 3/5 −( 2/10 )

</span><span>Simplify.
</span><span>m=5

The slope is 5</span>
3 0
3 years ago
In ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. What is the value of the sine of ∠R to the nearest hundreth
irina [24]

We have been given that in ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. We are asked to find the value of sine of ∠R to the nearest hundreth.

First of all, we will draw a right triangle using our given information.  

We know that sine relates opposite side of right triangle to hypotenuse.

We can see that side SR is hypotenuse and TS is opposite side to angle R.

\sin(\angle R)=\frac{SR}{TS}

\sin(\angle R)=\frac{65}{33}

\sin(\angle R)=1.96969

Upon rounding to nearest hundredth, we will get:

\sin(\angle R)\approx 1.97

Therefore, the value of the sine of ∠R is approximately 1.97.

3 0
3 years ago
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