The events are independent. By definition, it means that knowledge about one event does not help you predict the second, and this is the case: even if you knew that you rolled an even number on the first cube, would you be more or less confident about rolling a six on the second? No.
An example in which two events about rolling cubes are dependent could be something like:
Event A: You roll the first cube
Event B: The second cube returns a higher number than the first one.
In this case, knowledge on event A does change you view on event B (and vice versa): if you know that you rolled a 6 on the first cube you don't want to bet on event B, while if you know that you rolled a 1 on the first cube, you're certain that event B will happen.
Conversely, if you know that event B has happened, you are more likely to think that the first cube rolled a small number, and vice versa.
The taxes are figured as follows: 0.089(value of car)
Here the taxes are 0.089(value of car) = $1100.
Divide both sides of this equation by 0.089 to determine the value of the car.
value of car = $12359.55, or approx $12360.
Answer: Question 26: 39.2
Question 27: store B
Step-by-step explanation:
Answer:
Step-by-step explanation:
∠A + ∠B = 90° {given they are complementary}
5x+ 15 + 30 = 90
5x + 45 = 90
5x = 90 - 45
5x = 45
x = 45/5
x = 9
Perhaps you meant <span>(a^3+14a^2+33a-20) / (a+4), for division by (a+4).
Do you know synthetic division? If so, that'd be a great way to accomplish this division. Assume that (a+4) is a factor of </span>a^3+14a^2+33a-20; then assume that -4 is the corresponding root of a^3+14a^2+33a-20.
Perform synth. div. If there is no remainder, then you'll know that (a+4) is a factor and will also have the quoitient.
-4 / 1 14 33 -20
___ -4_-40 28___________
1 10 -7 8
Here the remainder is not zero; it's 8. However, we now know that the quotient is 1a^2 + 10a - 7 with a remainder of 8.
