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3 years ago

This drawing would be a step in finding which point of concurrency in a triangle?

Mathematics

1 answer:

tino4ka555 [31]3 years ago

5 0

Answer:

B. Orthocenter

Step-by-step explanation:

The orthocenter of a triangle is the point of intersection of the three altitudes (the perpendicular from a vertex to the side facing the vertex) of a triangle

The steps used in constructing the orthocenter includes the steps for drawing of the perpendicular to the sides of the triangle from a point which is the vertex opposite the side of the triangle

Therefore, in the given diagram, a perpendicular to the side KS is drawn from the (vertex) point W, by drawing an arc with center at W that intersects the side KS at two points. Rom the points of intersection of the arc drawn from W intersects KS, with the compass, two arcs are drawn to intersect at a point from which a line drawn to W, is perpendicular to KS

Therefore;

The correct option is B. orthocenter

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2 years ago

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melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

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To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

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3 years ago

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3 years ago

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