Answer: A=5/7. B=3/2. C=1/6
D=3/5. E=14/11. G=5/7 H=3/2 I=1/6 j=3/5 K=14/11 L=7/8
Step-by-step explanation:
Answer:
z=125
y=30
Step-by-step explanation:
x and z are the same because of the congruent sides then is triangle sum
Answer:
509.35 feet
Step-by-step explanation:
16°23' means 16 degrees and 23 minutes. A minute is 1/60 of a degree.
16°23' = 16 + (23/60) = 16.383°
Similarly:
49°29' = 49 + (29/60) = 49.483°
When the boat is first noticed:
tan(16.383°) = 200 / a
a = 200 / tan(16.383°)
a = 680.27
When the boat stops:
tan(49.483°) = 200 / b
b = 200 / tan(49.483°)
b = 170.92
So the difference is:
a − b = 680.27 − 170.92 = 509.35
The boat traveled 509.35 feet from the time it was first noticed to the time it stopped.
Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
Answer: B. 2 = 3x + 10x2
Step-by-step explanation:
This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:
[-3+-sqrt(3^2+4(10)(2))]/(2(10))
The formual that was applied here was a quadratic formula given by:
x=[-b+\-sqrt(b^2-4ac)]/2a
whereby from the our substituted values above,
a=10,b=3 and c=-2
such that the quadratic equation will be:
10x^2+3x-2
