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2 years ago

A bag contains colored tiles

Mathematics

1 answer:

Veseljchak [2.6K]2 years ago

4 0

Answer:

0.5

Step-by-step explanation:

6 is half of the tiles

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At which angle will the hexagon rotate so that it maps

Viefleur [7K]

Answer:

Step-by-step explanation:

3 0

3 years ago

What’s the answer ??? ( someone please help )

Fofino [41]

It would probably be B because it said between -30 and 130

3 0

2 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

2 years ago

The Sugar Sweet Company is going to transport its sugar to market. It will cost $7500 to rent trucks, and it will cost an additi

Inga [223]

Let C represent the total cost (in dollars),
and let S represent the amount of sugar (in tons) transported

equation:
C(s) = 225s + 7500

find the total cost to transport 11 tons of sugar.
C(11) = 225(11) + 7500
C(11) = 2475 + 7500
C(11) = 9975

hope it helps

7 0

2 years ago

Write the equation of the line in point-slope form that goes through the points (0, 1) and (2, 7)

laiz [17]

Answer:

point - slope form

y - 1 = 3 (x-0)

Step-by-step explanation:

step(i):-

Given points are (0,1) and (2,7)

The slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

$m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{7-1}{2-0} = \frac{6}{2} = 3$

m =3

Step(ii):-

point -slope form

y - y₁ = m(x-x₁)

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3

y - 1 = 3 (x-0)

y -1 = 3x

3x - y +1=0

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3 is 3x -y +1=0

4 0

2 years ago