Which quadratic equation fits the data in the table? x -5,-2,-1,0,3,4,6 y 33,9,5,3,9,15,33
mojhsa [17]
Answer:
y = x² − x + 3
Step-by-step explanation:
Quadratic equation is:
y = ax² + bx + c
Pick three points and plug in. I'll choose (-2, 9), (-1, 5), and (0, 3).
9 = a(-2)² + b(-2) + c
5 = a(-1)² + b(-1) + c
3 = a(0)² + b(0) + c
9 = 4a − 2b + c
5 = a − b + c
3 = c
We know c = 3, so substitute into the first two equations:
9 = 4a − 2b + 3
5 = a − b + 3
0 = 4a − 2b − 6
0 = a − b − 2
Solve by elimination or substitution.
b = a − 2
0 = 4a − 2(a − 2) − 6
0 = 4a − 2a + 4 − 6
0 = 2a − 2
a = 1
b = -1
Therefore:
y = x² − x + 3
The gcd of 5767 and 4453 is 73.
Hope this helps. :)
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Let 
. We have that 
if and only if we can find scalars 
such that 
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for 
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are 
, but note that for this values, the third equation doesn't hold (3+2 = 5 
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are 
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
