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3 years ago

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20% of the people in a village own a dog, 30% own goats and 40% own cattle, 5% own both a dog and goats, 4% own both a dog and c

attle and 3% own both goats and cattle. If 1% own all three, what percentage of the village own none of the three?

1 answer:

lana66690 [7]3 years ago

3 0

Answer:

37 %

Step-by-step explanation:

here..

only Dog = 20- 5 - 4 - 1 = 10

only goats = 30 - 5 - 3 - 1 = 21

only cattle = 40 - 4 - 3 - 1 = 32

then ... since the maximum percentage is 100 %

people who don't own any animal = 100% - 10% - 21% - 32% = 37 %

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$\frac{\frac{y^2-4}{x^2-9}} {\frac{y-2}{x+3}}$

Let us change middle bar to division sign.

$\frac{y^2-4}{x^2-9}\div \frac{y-2}{x+3}$

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ANSWER TO QUESTION 2

$\frac{1+\frac{1}{x}} {\frac{2}{x+3}-\frac{1}{x+2}}$

We change the middle bar to the division sign

$(1+\frac{1}{x}) \div (\frac{2}{x+3}-\frac{1}{x+2})$

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We now multiply with the reciprocal,

$(\frac{(x+1)}{x})\times \frac{(x+2)(x+3)}{(x+1)}$

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ANSWER TO QUESTION 3

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We rewrite the above expression to obtain;

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We now multiply by the reciprocal,

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Method 2: Changing the middle bar to a normal division sign.

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$\frac{19}{1}\times \frac{2}{37}$

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