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3 years ago

What is the slope and y-intercept for the line represented by this equation? 5x+13y= -13

1 answer:

3 0

In y = mx + b form, the slope will be in the m position and the y int will be in the b position. So, we need to put the equation in y = mx + b form.

5x + 13y = -13......subtract 5x from both sides
13y = -5x - 13...now divide both sides by 13
y = (-5/13)x -13/13
y = (-5/13)x - 1

so the slope is -5/13 and the y int is -1

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4 years ago

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marin [14]

Answer:

0.11

Step-by-step explanation:

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3 years ago

Write the equation of a line perpendicular to y=1/2x + 8 that passes through ( 4, 9 ).

iogann1982 [59]

Answer:y = - 2x + 17

Step-by-step explanation:

The equation of a line, represented in the slope-intercept form, is

y = mx + c

Where

Slope = m

c = intercept

Looking at the equation given,

y=1/2x + 8

Slope,m = 1/2

If a line is perpendicular to a another line, then the slope of one line is equal to the negative reciprocal of the other line. It means that the slope of the perpendicular line that passes through that passes through ( 4, 9 ) will be -2

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3 years ago

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k0ka [10]

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3 years ago