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2 years ago

12

What is the slope and y-intercept for the line represented by this equation? 5x+13y= -13

1 answer:

3241004551 [841]2 years ago

3 0

In y = mx + b form, the slope will be in the m position and the y int will be in the b position. So, we need to put the equation in y = mx + b form.

5x + 13y = -13......subtract 5x from both sides
13y = -5x - 13...now divide both sides by 13
y = (-5/13)x -13/13
y = (-5/13)x - 1

so the slope is -5/13 and the y int is -1

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Step-by-step explanation:

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$2x=\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{\sqrt{161}}{2}$

$x=\frac{\sqrt{161}}{2}$

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