We could use the Pythagorean theorem for this kind of problem I think:
A^2 + B^2 = C^2
6^2 + 16^2 = C^2
36 + 256 = C^2
292 = C^2
17.08 = C
C = 17.1 to the nearest tenth
Sorry if it’s wrong and glad I could help if it’s right ❤️❤️ Take care!
Given the equation: (km / 3) - 2x = 4, it is essential to isolate x to obtain the expression to solve it. This is done below:
(km / 3<span>) - 2x = 4
</span>
Adding 2x to both sides:
(km / 3<span>) - 2x + 2x = 4 + 2x
</span>(km / 3<span>) = 4 + 2x
</span>
Subtracting 4 from both sides:
(km / 3<span>) - 4 = 4 + 2x - 4
</span>(km / 3<span>) - 4 = 2x
</span>
Dividing 2 from both sides:
[(km / 3<span>) - 4] /2 = 2x /2
</span>[(km / 3<span>) - 4] /2 = x
</span>x = (km / 6) - 2
Answer:
-46
Step-by-step explanation:
5 (x - 2) - 14x. x=4
5 (4 - 2) - 14(4) (distribute)
20 - 10 - 14(4) (multiply)
20 - 10 - 56 (subtract and solve.)
10 - 56 = -46 - solution
hope this helps (:
Other guy is wrong the value of 17 does not matter in this question. 17 is the hypotenuse of the base triangles.
V = 1/2*a*c*h
V=1/2*15*15*8
V=225*4
V=900
The standard form of the quadratic equation is given by:
ax ^ 2 + bx + c
What we must do in this case is to rewrite the given equation.
We have then:
2/3 (x-4) (x + 5) = 1
(x-4) (x + 5) = 3/2
(x ^ 2 + 5x-4x-20) = 3/2
2x ^ 2 + 2x-40 = 3
2x ^ 2 + 2x-43 = 0
Thus, the values of a, b and c are:
a = 2
b = 2
c = -43
Answer:
a = 2
b = 2
c = -43
