<h3>
Answer: True</h3>
The key word here is "may" meaning that we could easily have 3 rational roots as well. An example of a cubic having 3 irrational roots would be
(x-1)(x-2)(x-3) = x³ - 6x² + 11x - 6
This has the rational roots x = 1, x = 2, x = 3.
However, we could easily replace 1,2,3 with any irrational numbers we want. So that's why the statement "a cubic has three irrational roots" is sometimes true.
In some cases, a cubic may only have 1 real root and the other 2 roots are imaginary.
If you would like to know which quotient will be negative, you can find this using the following steps:
24 / 6 = 4
-35 / 7 = -5
-54 / (-6) = 9
3 / (-1) = -3
Answer:
The answer is 8 units! Hope this helps!
Step-by-step explanation:f the length of any one side of the square is x, then the area is x2, and the perimeter is 4x. If the area is twice the perimeter, x2 = 2(4x), and x2 − 8x= 0. By factoring, we see this equation is equivalent to x(x − 8) = 0, which has solutions 0 and 8. The length cannot be 0, so it must be 8 units.
X+2y=2 …(1)
x-2y=-2…(2)
(1)-(2): (x+2y)-(x-2y)=2- (-2)
4y=4
y=1
subs y=1 into(1)
x+2(1) =2
x=0
so x =0 y=1
the answer is C
