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3 years ago

The local cell phone tower services for your provider

Mathematics

1 answer:

Artemon [7]3 years ago

8 0

Answer: Quick Ways to Find Cell Towers Near You:

Use an App like Open Signal, Network Cell Info Lite, or Cellular Network Signal Finder. Rely on Your Smartphone's Antenna – Find instructions below. Try a cell phone signal booster to capture the signal from nearby cell towers.J

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It would be lovely if you answered this (97 points)

zimovet [89]

Dcaebf is the answer.

4 0

3 years ago

Read 2 more answers

A rectangle has an area of 4 square centimeters. A second rectangle is 3 times as long and 3 times as wide as the first rectangl

vekshin1

Answer:

The area of the second rectangle will be 36 square centimetres

Step-by-step explanation:

Given:

Area of the first rectangle = 4 square centimetres

A second rectangle is 3 times as long and 3 times as wide as the first rectangle

To Find:

Area of the second rectangle = ?

Solution:

We know that area of the rectangle is Length X breadth

Length X width = 4

In this case the are 2 possibilities

Case 1:

Length = 2 cm

Width = 2 cm

2 X 2 = 4

Now According to the question

Length is 3 times = 2 X 3 = 6cm

width is also 3 times = 2 X 3 = 6 cm

Now the area of the second rectangle will be

6 X 6 = 36 square centimetres

Case 2:

Length = 4 cm

Width = 1 cm

4 X 1 = 4

Now According to the question

Length is 3 times = 4 X 3 = 12 cm

width is also 3 times = 1 X 3 =3 cm

Now the area of the second rectangle will be

12 X 3 = 36 square centimetres

5 0

3 years ago

Need help with 56 plz!

Naddika [18.5K]

Answer: No idea, sorry. I'm sure you could look it up tho

Step-by-step explanation:

3 0

3 years ago

Ali was swimming along the bottom of his backyard pool at a depth of 6 feet then he pushed off the bottom and rose 4 feet what i

olga nikolaevna [1]

Answer:

2 feets

Step-by-step explanation:

Given that :

Alli's Initial depth = 6 feets

Number of feets in which Alli rose = 4 feets

Alli's new position relative to the surface of the pool:

Difference of Alli's initial depth and feets risen :

6 feets - 4 feets = 2 feets

Hence, Alli is now 2 feets below the surface of the pool.

7 0

3 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago