A captain is twice as old as his ship was when he was as old as his ship is now.

Zinaida [17]

Either:
y-8=2(x+3)
y-8=2x+6
-2x+y=14

or

y-8=2(x+3)
y=2x+14

5 0

3 years ago

En una fiesta se desea elegir un grupo de 3 personas de entre 6 matrimonios, si dos miembros de la misma pareja no pueden ser el

LenaWriter [7]

Answer:

Hay 160 maneras

Step-by-step explanation:

Para calcular de cuántas maneras se puede seleccionar x elementos de un grupo de n elementos podemos usar la siguiente fórmula:

$nCx=\frac{n!}{x!(n-x)!}$

Si vas a elegir 3 personas de entre 6 matrimonios y dos miembros de la misma pareja no pueden ser elegidos, entonces podemos decir que se está eligiendo 3 matrimonios y en cada matrimonio se está eligiendo un representante.

Entonces, podemos calcular de cuántas maneras se puede escoger 3 matrimonios de los 6, así:

$6C3=\frac{6!}{3!(6-3)!}=20$

Adicionalmente, para cada uno de los 3 matrimonios hay 2 opciones para ser representantes. Esto significa que hay $2^3$ maneras de escoger representantes en cada una de las 20 formas calculadas anteriormente.

Por lo tanto se puede formar el grupo de 3 personas de 160 maneras diferentes:

$20*2^3=160$

6 0

3 years ago

Given that OA = 2x + 9y, OB = 4x + 8y and CD = 4x - 2y, explain the geometrical relationships between the straight lines AB and

Step2247 [10]

Answer:

The geometrical relationships between the straight lines AB and CD is that they have the same slope

Step-by-step explanation:

Given

$OA = 2x + 9y$

$OB = 4x + 8y$

$CD = 4x - 2y$

Required

The relationship between AB, CD

Since AB is a straight line and O is the origin, then:

$AB = (c - a)x + (d - b)y$

Where:

$OA = ax + by$ ====> $OA = 2x + 9y$

$OB = cx + dy$ ====> $OB = 4x + 8y$

This implies that:

$a =2$ $b = 9$ $c = 4$ $d = 8$

So:

$AB = (c - a)x + (d - b)y$

$AB = (4 - 2)x + (8 - 9)y$

$AB = 2x -y$

So, we have:

$AB = 2x -y$

$CD = 4x - 2y$

Calculate the slope (m) of $AB\ and\ CD$

$m = \frac{Coefficient\ of\ y}{Coefficient\ of\ y}$

For AB

$m_1 = \frac{-1}{2}$

$m_1 = -\frac{1}{2}$

For CD

$m_2 = \frac{-2}{4}$

$m_2 = \frac{-1}{2}$

$m_2 = -\frac{1}{2}$

By comparison:

$m_1 = m_2 = -\frac{1}{2}$

This implies that both lines have the same slope

8 0

3 years ago

How do you know if the question is asking for you to do Pythagoras or Trigonometry? Like in basic terms, what’s the difference??

mrs_skeptik [129]

Pythagoras theorem only works for right triangle (90 degree)

Trigonometry (sin, cos, tan) works everywhere!

Hopefully I answered your question!

If you want to learn more about Trigonometry or Pythagoras theorem, send me a message and add me as friend on Brainly. I'm a mathematician and an astrophysicist

:) have a great day!

7 0

3 years ago

A process is controlled with a fraction nonconforming control chart with three-sigma limits, n = 100, UCL = 0.161, center line =

photoshop1234 [79]

Answer:

Lets Recall, p= 0.080, n=100, UCL= 0.161

Then np=100, 0.080=8

Step-by-step explanation:

The full steps or solution to this is in an an attached document.

4 0

3 years ago