All u do is just replace f with 2/3x+5 then solve
Answer:
A,C,F,G,H
Step-by-step explanation:
According to the given statement the radius of the circle before dilation is 1/2ft and the scale factor is 8. The dilation by scale factor 8 means the radius of new circle is 8 times of the original circle(4ft)
The circumference of the circle is 2πr.
If we replace r by 8r and substitute it in the formula then the circumference will be:
C=2π(8r)
C=8*(2πr)
It means the circumference is 8 times the original circumference.
Now put the value of original circle radius in this new circumference we get:
C=8*(2πr)
C=8*(2π*1/2)
C=8πft
Now the area of the circle = πr^2
Now put the value of r replaced by 8r in the formula.
A=π(8r)^2
A=64πr^2
Thus the area will be 64 times by the original circle area
If we plug the value of original circle radius in this new formula of area we get.
A=64πr^2
A=64π(1/2)^2
A= 16πft^2
Thus the correct statements are: A, C, F,G,H....
If these two lines are parallel, they would have the same gradient.
Since Gradient = Rise / Run,
8 / -12 : -4 / 1
These two ratios are obviously not the same, so we can conclude the lines are not parallel.
Answer:
x = 58/3
Step-by-step explanation:
We can use cross products to solve this problem
6 7
---------- = -----------
14 x-3
6 * (x-3) = 7 * 14
Divide each side by 6
6 /6* (x-3) = 7 * 14/6
x-3 = 98/6
Add 3 to each side
x-3+3 = 98/6 +3
x = 98/6 +18/6
x = 116/6
Divide the top and bottom by 2
x =58/3
