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mylen [45]
3 years ago
10

6 is added to four times a number the result is 50 Find the number

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0

Let "a number" = x

4x + 6 = 50 is your equation

Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

Subtract 6 from both sides

4x + 6 (-6) = 50 (-6)

4x = 44

Divide 4 from both sides

4x/4 = 44/4

x = 44/4

x = 11

11 is your answer for the number

hope this helps

Lady_Fox [76]3 years ago
4 0

This is how you do it. You just solve for x.

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Roger has 2 1/2 cups of butter. A recipe for a loaf of bread requires 3/4 cups of butter. How many loaves can Roger bake?
lubasha [3.4K]
The number of loaves can be determined with dividing the butter by the number of cups needed for a loaf.
loaves = 2 1/2 ÷ 3/4

Change into improper fraction
loaves = 2 1/2 ÷ 3/4
loaves = 5/2 ÷ 3/4

Change into multiplication
loaves = 5/2 ÷ 3/4
loaves = 5/2 × 4/3
loaves = 20/6
loaves = 10/3
loaves = 3.3
Because the number of loaves can't be a fraction, round it to the smaller whole number

Roger can make 3 loaves of bread
7 0
3 years ago
Read 2 more answers
(1 point)
Rashid [163]
The third one is the answer for this question
3 0
3 years ago
What is the value of this expression when c=-4 and d = 10?<br> 1/4(c3+d2)
Mumz [18]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the value of this expression when c = -4 and d = 10 ? \frac{1}{4} (c³ + d²)

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

\frac{1}{4} (c³ + d²) where c = -4 and d = 10

<h3>To Find:-</h3>

The value of the expression \frac{1}{4} (c³ + d²)

<h2>Solution:-</h2>

\frac{1}{4} (c³ + d²) [Given expression]

Now, putting the value of c = -4 and d = 10 , we get,

\frac{1}{4} { (-4)³ + (10)² }

\frac{1}{4} ( -64 + 100 )

\frac{1}{4} ( 36 )

\frac{1}{4} × 36

\bf = \: 9 \: ( Answer )

3 0
3 years ago
What is the value of x?
Phantasy [73]

Answer:

value of x = 5.8 mm

Step-by-step explanation:

We have given,

Two right triangles EDH and EDG.

In right triangle EDH, EH = 56mm , DH = 35 mm

Using Pythagoras theorem we can find ED.

i.e EH² = ED²+DH²

56²=ED²+35²

ED²=56²-35²

ED = √(56²-35²) = 7√39 = 43.71 mm

Now, Consider right triangle EDG

Here, EG=44.8mm , GD = x+4  and ED = 7√39

Again using Pythagoras theorem,

EG² = ED² + DG²

44.8²= (7√39)²+ (x+4)²

(x+4)² = 44.8² - (7√39)²

x+4 = √(44.8² - (7√39)²)

x+4 = 9.8

or x = 9.8 - 4 = 5.8 mm

Hence we got the value of x = 5.8 mm

6 0
3 years ago
F(x)=4x2−8x−60 f(x)=4(x2−2x−15) f(x)=4(x−5)(x+3) whts the true statement of f(x)
alukav5142 [94]

Answer: D


Step-by-step explanation:

No such thing as a vertex of a graph... Eliminate B and C. Try f(3) = 4(3-5)(3+3) is not zero eliminate A. So answer must be D. Check: f(-3) has factor -3+3 = 0. f(5) has factor 5-5 = 0.

4 0
3 years ago
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