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marusya05 [52]
3 years ago
5

En una fiesta se desea elegir un grupo de 3 personas de entre 6 matrimonios, si dos miembros de la misma pareja no pueden ser el

egidos para formar parte de ese grupo. De cuantas maneras diferentes se puede formar el grupo de 3 personas?
Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

Hay 160 maneras

Step-by-step explanation:

Para calcular de cuántas maneras se puede seleccionar x elementos de un grupo de n elementos podemos usar la siguiente fórmula:

nCx=\frac{n!}{x!(n-x)!}

Si vas a elegir 3 personas de entre 6 matrimonios y dos miembros de la misma pareja no pueden ser elegidos, entonces podemos decir que se está eligiendo 3 matrimonios y en cada matrimonio se está eligiendo un representante.

Entonces, podemos calcular de cuántas maneras se puede escoger 3 matrimonios de los 6, así:

6C3=\frac{6!}{3!(6-3)!}=20

Adicionalmente, para cada uno de los 3 matrimonios hay 2 opciones para ser representantes. Esto significa que hay 2^3 maneras de escoger representantes en cada una de las 20 formas calculadas anteriormente.

Por lo tanto se puede formar el grupo de 3 personas de 160 maneras diferentes:

20*2^3=160

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