Transitive property of addition
I think the person on top got you with the answer
Answer:
(1,155, 1.545).
Step-by-step explanation:
From Normal distribution tables the z score for 95% CI = 1.96.
Confidence Interval
= 1.35 +/- 1.96 * 0.63/√40
= 1.35 +/- 0.195
= (1,155, 1.545).
(-6y-2)+5(3+2.5y) expend
-6y-2+15+12.5
6.5y+13
