Answer:
I can't answer the whole question but the first one is 7 x 9, or 63 squares. And say you chose a square that is 4 x 3 so that would be the area of the tile you chose. Im sorry I couldn't answer the whole thing but I hope that makes since of what I did, if not please ask questions.
Step-by-step explanation:
Slope = (-2 + 4)/(-2-2) = 2/-4 = -1/2
y = mx + b
so
b = y - mx
b = -2 -(-1/2)(-2)
b = -2 - 1
b = - 3
equation
y = -1/2x - 3
answer is B.
y = -1/2x - 3
<h3>
Answer: Choice C</h3>
{x | x < -12 or x > -6}
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Explanation:
Let's solve the first inequality for x.
(-2/3)x > 8
-2x > 8*3
-2x > 24
x < 24/(-2)
x < -12
The inequality sign flips when we divide both sides by a negative value.
Let's do the same for the second inequality.
(-2/3)x < 4
-2x < 4*3
-2x < 12
x > 12/(-2)
x > -6
The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.
Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.
Step-by-step explanation:
A Maclaurin series is a Taylor series that's centered at 0.
f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(0) / n! xⁿ
If we substitute f⁽ⁿ⁾(0) = (n + 1)!:
f(x) = ∑ₙ₌₀°° (n + 1)! / n! xⁿ
f(x) = ∑ₙ₌₀°° (n + 1) xⁿ
Use ratio test to find the radius of convergence.
lim(n→∞)│aₙ₊₁ / aₙ│< 1
lim(n→∞)│[(n + 2) xⁿ⁺¹] / [(n + 1) xⁿ]│< 1
lim(n→∞)│(n + 2) x / (n + 1)│< 1
│x│< 1
R = 1