The answer is: "4" .
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<u>Note</u>: The question asks for a whole number.
"The area of the triangle above will equal one half of a rectangle that is 5 units long and <u> 4 </u><u /> units wide. (Input only whole numbers, such as 8.).
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<u>Note</u>: The diagram shows a "right triangle" ; which would be "one-half" of a rectangle, with units of "length" being "5 units" (as mentioned in this very question prompt; and a width of "4" units (as shown in the diagram; hence the answer is "4" units).
Furthermore, the formula/equation for the area, "A" , of a triangle is:
A = (1/2) * b * h ;
that is:
Area = (1/2) * (base length) * (perpendicular height).
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As such, the answer, "4" (units) makes sense.
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Answer:
Step-by-step explanation:
Rise over run. Difference in y values is rise. 4.25 -6 is -1.75. Run s difference in x values. 12.5 -7 is 5. Divide -1.75/5 to get -0.35 As a faction thats -7/20
Answer:
GF = 16.25
Step-by-step explanation:
If G is the circumcenter of triangle ABC, AG = 6x + 1, GC = 9x – 11, and BC = 38, find GF.
Step 1
We find x
AG = GC
6x + 1 =9x - 11
Collect like terms
1 + 11 = 9x - 6x
12 = 3x
x = 12/3
x = 4
Step 2
We solve for AG
GC = 9x + 11
GC = 9(4) + 11
GC = 36 + 11
GC = 25
Step 3
Solving for GF, using Pythagoras Theorem
GF² + BG² = GC²
GF² = GC² - BG²
GF = √GC² - BG²
GF = √25² - 19²
GF = √264
GF = 16.248076809
GF = 16.25
Answer:
is the simplest form of given expression.
Step-by-step explanation:
The given question is 
To solve the problem we have to group or split middle term and then factorise

Taking
common from first two terms of denominator and 2 from next two terms

Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


Now cancel out x-1 from both numerator and denominator we get
is the required simplest form.
Answer:
Answer:
Distance is 13.6 units.
Which means it is 13
Step-by-step explanation:
Given a grid shows the positions of subway stop and house. The subway stop is located at (-7, 8) and house is located at (6, 4).
we have to find the distance between house and the subway stop.
Points are (-7, 8) and (6, 4).
Using distance formula,
D= /(x2-x1)^2+(y2-y1)^2} = (6-(-7))^2+(4-8)^2=(13)^2+16}={169+16}={185}=13.60147\sim13.6units.
Hence, distance between house and the subway stop is 13.6 units.