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Marysya12 [62]
3 years ago
14

Number 2 the table shows the gas mileage of two vehicles. Which vehicle travels more miles per gallon? Car. Miles. Gallons. Pick

up truck 120. 8. Minivan. 180. 10

Mathematics
2 answers:
aliina [53]3 years ago
4 0

Answer:

The minivan travels more miles per gallon

Step-by-step explanation:

To determine the unit rate, take the miles and divide by the gallons

Truck:

120 miles / 8 gallons =15 miles per gallon

Minivan:

180 miles /10 gallons = 18 miles per gallon

The minivan travels more miles per gallon

Inessa [10]3 years ago
4 0

Answer: Minivan

Step-by-step explanation:

Find the unit rates by dividing the miles by the gallons

Pickup Truck:

miles/gallons

120/8=15

15 miles per gallon

Minivan:

miles/gallons

180/10=18

18 miles per gallon

So, the minivan travels more miles per gallon, because 18 is greater than 15.

Hope this helps! :)

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Jayce is a taxi driver.
REY [17]

Answer:

Jayce's fee (in dollars) for 10th drive on a certain day is K.

Step-by-step explanation:

It is given that M(n) models Jayce's fee (in dollars) for nth drive on a certain day.

We need to find the meaning of M(10)=K.

On comparing M(n) and M(10), we get the value of n is 10.

Since M(n) represents the Jayce's fee (in dollars) for nth drive on a certain day, therefore, M(10) represents the Jayce's fee (in dollars) for 10th drive on a certain day.

M(10)=K

It means Jayce's fee (in dollars) for 10th drive on a certain day is K.

8 0
4 years ago
Sin∅=√3-1/2 find approximate value of sec∅(sec∅+tan∅)/1+tan²∅​
Neko [114]

Answer:

The approximate value of f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta} is 1.366.

Step-by-step explanation:

Let f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}, we proceed to simplify the formula until a form based exclusively in sines and cosines is found. From Trigonometry, we shall use the following identities:

\sec \theta = \frac{1}{\cos \theta} (1)

\tan\theta = \frac{\sin\theta}{\cos \theta} (2)

\cos^{2}+\sin^{2} = 1 (3)

Then, we simplify the given formula:

f(\theta) = \frac{\left(\frac{1}{\cos \theta} \right)\cdot \left(\frac{1}{\cos \theta}+\frac{\sin \theta}{\cos \theta}\right) }{1+\frac{\sin^{2}\theta}{\cos^{2}\theta} }

f(\theta) = \frac{\left(\frac{1}{\cos^{2} \theta} \right)\cdot (1+\sin \theta)}{\frac{\sin^{2}\theta + \cos^2{\theta}}{\cos^{2}\theta} }

f(\theta) = \frac{\left(\frac{1}{\cos^{2}\theta}\right)\cdot (1+\sin \theta)}{\frac{1}{\cos^{2}\theta} }

f(\theta) = 1+\sin \theta

If we know that \sin \theta =\frac{\sqrt{3}-1}{2}, then the approximate value of the given function is:

f(\theta) = 1 +\frac{\sqrt{3}-1}{2}

f(\theta) = \frac{\sqrt{3}+1}{2}

f(\theta) \approx 1.366

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Step-by-step explanation:

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