Complete Question: A +10 nC charge is located at the origin. What is the electric field at the position (x2,y2)= (-5.0cm, 0cm)? Write electric field vector in component form.
E2x, E2y=? N/C
Answer:
Ex = -3.6*10⁴ N/C Ey=0
Explanation:
As the charge producing the field is positive, the direction of the field, which is the one that would take a positive test charge located in the point of interest, will be away from this point, pointing to the left.
If we choose the positive direction to be to the right, the electric field component along the x-axis will be negative.
The magnitude of the field can be obtained applying the electric field definition, and the Coulomb's Law to the charge in the origin, as follows:
E = k*q/r² = 9*10⁹N*m²/C²*10⁻⁸C/(0.05)² m² = 3.6*10⁴ N/C
As the electric field follows the same line as the electric force, it has only component on the x axis, so:
Ex = -3.6*10⁴ N/C
Ey = 0
<span>Following both the statements are true:
Some Defined it by
"Supported by most but not all".
Some defined it by this statement:
</span>"Not studied by many scientists"
Answer:
The two forms of energy that increase during the time after take off are;
1) The kinetic energy KE
1) The potential energy PE
Explanation:
1) Given that the airplane is accelerating, we have that the velocity, v, of the airplane is increasing, such that the we have the kinetic energy, KE, for a given mass, m, of the airplane increasing as follows;
KE₂ = 1/2×m×v₂² > KE₁ = 1/2×m×v₁²
2) Also, as the height, h, of the airplane increases during the ascent, we have that the potential energy increasing along side as follows;
PE₂ = m × g × h₂ > PE₁ = m × g × h₁
Therefore, the two forms of energy that increase during the time after take off are the kinetic and the potential energy.
The correct answer is electromagnetic. Lights travel as an electromagnetic wave. In fact, light is an electromagnetic radiation which has a center of the electromagnetic spectrum. Light is visible to the naked eye, and is responsible for an organism's sense of sight.