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postnew [5]
3 years ago
5

Light travels as a(n) _______ wave. mechanical compression electromagnetic

Physics
2 answers:
Alex787 [66]3 years ago
8 0

Answer: The correct answer is "electromagnetic wave".

Explanation:

Electromagnetic waves: These waves are produced by vibration of the charged particles. But the mechanical waves are caused by wave amplitude.

Electromagnetic wave does not need a medium while the mechanical wave needs a medium to travel.

The electromagnetic wave travels with the speed of the light. The example of electromagnetic wave is light.

Mechanical waves are of two types: Longitudinal wave and Transverse.

Sound wave is a longitudinal wave. It consists of compression and rarefaction.

Therefore, Light travels as an electromagnetic wave.

Ugo [173]3 years ago
4 0
The correct answer is electromagnetic. Lights travel as an electromagnetic wave. In fact, light is an electromagnetic radiation which has a center of the electromagnetic spectrum. Light is visible to the naked eye, and is responsible for an organism's sense of sight.
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What is the strength of the electric field in a region where the electric potential is constant?
Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx        ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

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3 years ago
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Anni [7]

Answer:

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Explanation:

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2 years ago
Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.
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nadezda [96]

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8 0
3 years ago
A cannon, positioned on a hill, shoots a cannonball horizontally at 23 m/s. The cannonball hits the stone wall 1.96 m below the
irina [24]

Answer: 14. 49 m

Explanation:

We can solve this problem with the following equations:

x=V_{o} cos \theta t (1)

y-y_{o}=V_{o} sin \theta t-\frac{1}{2}gt^{2} (2)

Where:

x is the horizontal distance between the cannon and the ball

V_{o}=23 m/s is the cannonball initial velocity

\theta=0\° since the cannonball was shoot horizontally

t is the time

y=0 is the final height of the cannonball

y_{o}=1.96 m is the initial height of the cannonball

g=9.8 m/s^{2} is the acceleration due gravity

Isolating t from (2):

t=\sqrt{-\frac{2(y-y_{o})}{g}} (3)

t=\sqrt{-\frac{2(0 m-1.96 m)}{9.8 m/s^{2}}} (4)

t=0.63 s (5)

Substituting (5) in (1):

x=(23 m/s) cos(0\°) 0.63 s (6)

Finally:

x=14.49 m

5 0
3 years ago
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