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Answer:
72.75 kg m^2
Explanation:
initial angular velocity, ω = 35 rpm
final angular velocity, ω' = 19 rpm
mass of child, m = 15.5 kg
distance from the centre, d = 1.55 m
Let the moment of inertia of the merry go round is I.
Use the concept of conservation of angular momentum
I ω = I' ω'
where I' be the moment of inertia of merry go round and child
I x 35 = ( I + md^2) ω'
I x 35 = ( I + 25.5 x 1.55 x 1.55) x 19
35 I = 19 I + 1164
16 I = 1164
I = 72.75 kg m^2
Thus, the moment of inertia of the merry go round is 72.75 kg m^2.
The magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.
<h3>What is magnetic field strength?</h3>
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
The magnetic field strength is found as;

In the formula,I denote current, and r denotes the distance between the point and the current carrying wire and magnetic field due to current in the bottom wire.
At point 1, the net magnetic field is found as the sum of magnetic field due to current in the top wire.


Hence, the magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.
To learn more about the strength of induced magnetic field, refer:
brainly.com/question/2248956
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