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STALIN [3.7K]
3 years ago
10

Hi hello hola wow omg peepoopeepoo

Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer: Helloooo

Step-by-step explanation:

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Nathan helps out in the family pet shop on Saturdays. He must separate a shipment of 112 fish into nine bowls. Does Nathan have
Olin [163]
He has 9 bowls...and each bowl holds ,at most, 12 fish...so he can house (12 * 9) = 108 fish at most.

so... no, he does not have enough bowls ....he only needs one more bowl
7 0
3 years ago
Read 2 more answers
The area of trapezoid TRAP is 100. Furthermore, TR=32, AP=8, and TP=RA. If
saw5 [17]

Answer:

  TP = 13

Step-by-step explanation:

The height of the trapezoid can be found from the area formula:

  A = (1/2)(b1 +b2)h

  h = 2A/(b1 +b2) = 2(100)/(32 +8)

  h = 5

The horizontal length of each triangular end of the trapezoid is ...

  (32 -8)/2 = 24/2 = 12

so the hypotenuse of the triangular end of the trapezoid is ...

  TP = √(12^2 +5^2) = √169

  TP = 13

The sides of the trapezoid have length 13 units.

4 0
3 years ago
Find the gcf of 12 and 45
krek1111 [17]

gcf = 3

the factors of 12 are 1, 2, 3, 4, 6 and 12

the factors of 45 are 1, 3, 5, 9, 15 and 45

the greatest common factor of 12 and 45 is 3


3 0
4 years ago
Read 2 more answers
find the missing value so the line passing through the points has the given slope.(10,y) and (3,4);m=3/4
Hoochie [10]

Answer:

The value of y is 9¼.

Explanation:

Given that the slope of the set of points (10,y) and (3,4) is 3/4.

Using the slope formula:

\text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}

We have:

\frac{3}{4}=\frac{4-y}{3-10}

We then solve for y:

\begin{gathered} \frac{3}{4}=\frac{4-y}{-7} \\ \text{Cross multiply:} \\ 4(4-y)=-21 \\ 16-4y=-21 \\ -4y=-21-16 \\ -4y=-37 \\ y=\frac{-37}{-4} \\ y=9\frac{1}{4} \end{gathered}

The value of y is 9¼.

3 0
1 year ago
Solve the inequality: 5x + 14 greater than or equal too 54
White raven [17]

Answer:

5*8+14=54

Step-by-step explanation:

5*x+14= 54

so

54-14= 40

40/5=8

so x=8

7 0
3 years ago
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