Hello!
This is the Question you means right? vvvvvv
"Sarah decides to take her six year old son to the circus. The price for the child's ticket is 4.75 dollars less than the price for the adult's ticket. If you represent the price for the child's ticket using the variable "x," how would you write the algebraic expression for the adult's ticket price? 4.75x x + 4.75 x over 4.75 x4.75"
^^^^^^
If So, The Correct Answer would be:
Option "B". Why?
Let x be the cost of the child ticket Let y be the cost of the adult ticket The adult ticket is $4.75 more than the child ticket.
How would you write the algebraic expression for the adult's ticket price? y = $4.75 + x Which option is that? "B"
adult ticket = y
<span>child ticket = x </span>
<span>y = 4.75 + x
</span>
Hope this Helps! Have A Wonderful Day! :)
Answer:
Step-by-step explanation:
The circumference for a circle is found in the formula
![C=\pi d](https://tex.z-dn.net/?f=C%3D%5Cpi%20d)
so if the diamteter is 7, then the circumference is
or if you are told to round to the nearest hundredth or thousandth, multiply pi in as 3.1415 to get that the circumference is 21.9905 cm
The right answer is Option A: pq(p+1)(p-1)
Step-by-step explanation:
Given expression is
![p^3q-pq](https://tex.z-dn.net/?f=p%5E3q-pq)
Taking pq common from the expression
![pq(p^2-1)](https://tex.z-dn.net/?f=pq%28p%5E2-1%29)
We know that;
![a^2-b^2=(a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29)
Here;
![a^2 = p^2\\b^2 = 1^2](https://tex.z-dn.net/?f=a%5E2%20%3D%20p%5E2%5C%5Cb%5E2%20%3D%201%5E2)
Therefore;
![p^2-1=(p+1)(p-1)](https://tex.z-dn.net/?f=p%5E2-1%3D%28p%2B1%29%28p-1%29)
Thus, the expression becomes
![pq(p+1)(p-1)](https://tex.z-dn.net/?f=pq%28p%2B1%29%28p-1%29)
The linear factors of
are pq(p+1)(p-1)
The right answer is Option A: pq(p+1)(p-1)
Keywords: linear factors, common terms
Learn more about linear factors at:
#LearnwithBrainly
5d<32+13
5d<45
D<9
Just simplify as much as you can.