Answer:
Step-by-step explanation:
You have to write in y = mx + c form
3x - 5y = 25
-5y = -3x - 25
Answer:
x ∈ (- 9/2; 1/2), it can also be written as -9/2 <x< 1/2
Step-by-step explanation:
We have absolute value, so we will have2 inequalities.
2x + 4 < 5 and -(2x +4)< 5
2x < 1 -2x - 4 < 5
x < 1/2 -2x < 9
or x > -9/2
(-∞; 1/2) or (- 9/2; ∞)
(-∞; 1/2) ∩ (- 9/2; ∞) = (- 9/2; 1/2)
The answer is x ∈ (- 9/2; 1/2), it can also be written as -9/2 <x< 1/2.
Let z = √3 + i. Compute the modulus and argument of z :
|z| = √((√3)² + 1²) = √4 = 2
arg(z) = arctan(1/√3) = π/6 = 30°
Then
z = √3 + i = 2 (cos(30°) + i sin(30°))
Replace x with the value in the table and solve for y
-3: 2(-3)/3 + 4 = -6/3 + 4 = -2+4 = 2
0: 2(0)/3 +4 = 0/3 + 4 = 0+4 = 4
3: 2(3)/3 + 4 = 6/3 + 4 = 2 + 4 = 6
6: 2(6)/3 + 4 = 12/3 + 4 = 4+4 = 8