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sp2606 [1]
2 years ago
11

A rectangular garden has a walkway around it. The area of the garden is 6(5.5x + 1.5). The combined area of the garden and the w

alkway is 7.5(8x + 4). Find the area of the walkway around the garden as the sum of two terms.
...
The area of the walkway around the garden is
Mathematics
1 answer:
Anika [276]2 years ago
3 0

Answer:

The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

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What is 0.9(x-20)=830 Rounded to the Hundreths (second) decimal place
enot [183]

Answer:

x= 942.22

Step-by-step explanation:

.9x-18=830

.9x=848

x=942.222222222

which will be x= 942.22

4 0
3 years ago
Find the value x and write the property used here.
Serga [27]

Step-by-step explanation:

Soln,

Here,

45°+65°+y(let)=180°[ being a triangle]

or,110°+y=180°

or,y=180°-110°

so,y=70°

Now,

x=?

so,

x+y=180°[being straight angle]

or,x+70°=180°

or,x=180°-70°

x=110°

THEREFORE,x=110°

solved!

6 0
2 years ago
Read 2 more answers
Please help I don’t wanna add a bunch of points Bc nobody is helping me I’m just wasting them.
Ede4ka [16]

Answer:Cross multiply and solve for x.

x/6 = 5/1.25

let the height of building be h ft

h/6 = 60/15

h = 6(60/15) = 24

the building is 24 ft high

Step-by-step explanation:

Well first let’s covert the ft to in- 5ft is 60 in and 6ft is 72 in. Then we want to set up 2 fractions based on height and shadow, so we have 60/15=x/72 (we put x because that’s what we’re trying to find). Then we do cross multiplication so now we have 15x=4320. We divide 15, so now we have 4320/15=288. So the building is 288 in tall or 24ft tall! Glad to help! :)

3 0
2 years ago
What is the value of X?
zhenek [66]
Tough sorry wish I could help u can’t too hard but I think it is equivalent to the other triangle so I think it’s 31? I THINK
7 0
3 years ago
Read 2 more answers
7) Find the area of the shaded region:
aleksandr82 [10.1K]

Answer:

B

Step-by-step explanation:

The area of the biggest rectangle =

(9x - 2)(2x + 7) = 18 {x}^{2}  + 63x - 4x - 14  = 18 {x}^{2}   + 59x - 14

The area of the of the smallest rectangle inside=

3x(x + 12) = 3 {x }^{2}  + 36x

Then the area of the shaded region =

18 {x}^{2}  + 59x - 14 - (3 {x}^{2}   + 36x)    = 18 {x}^{2}  + 59x - 14 - 3 {x}^{2}  - 36x = 15 {x}^{2}  + 23x - 14

So, we choose B.

7 0
3 years ago
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