Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
_____
<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.
You answer would be Oy= 7x-1. I hope this helps!
First you substitute in the values so you have
V^2=(64)20
then you just simplify it
V^2=1280
V=the square root of 1280
V= about 35.7770876
or
V=the square root of 256 times <span>the square root of 5
V=16 times </span><span>the square root of 5
also V would typically be called velocity. it's very similar to speed but it is just easier to remember because it starts with a V</span>
Answer:
11M + 2X + 8
Step-by-step explanation:
Hope this helps!! :))
Final Answer: 
Steps/Reasons/Explanation:
Question: What is the solution to the linear equation
?
<u>Step 1</u>: Simplify
to
.

<u>Step 2</u>: Cancel
on both sides.

<u>Step 3</u>: Subtract
from both sides.

<u>Step 4</u>: Simplify
to
.

<u>Step 5</u>: Divide both sides by
.

~I hope I helped you :)~