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krek1111 [17]
3 years ago
15

The perimeter of the fig

Mathematics
2 answers:
adoni [48]3 years ago
6 0
Add all the sides 11+4+5+16+10=46 so the perimeter of this figure is 46 Hope this Helps :)
mr_godi [17]3 years ago
5 0
4+16+10+5+11+6=52yd
Hope I helped

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4 raised to power two minus 8u minus 9=0​
coldgirl [10]

Answer:

x can be 3, -3, i, or -i.

Step-by-step explanation:

If you can't find the factoring by looking at this, simplify the equation.

let  

x

2

=

y

to make things easier to see

Now we have  

y

2

−

8

y

−

9

=

0

See it now?

We can factor into  

(

y

−

9

)

(

y

+

1

)

Now substitute back in  

x

2

for  

y

.

(

x

2

−

9

)

(

x

2

+

1

)

Since  

(

x

2

−

9

)

is a difference of two squares,

(

x

−

3

)

(

x

+

3

)

Now we have  

(

x

−

3

)

(

x

+

3

)

(

x

2

+

1

)

x can be 3, -3 for the first two parts

x

2

+

1

=

0

can become  

x

2

=

−

1

Taking the positive and negative root means  

x

=

±

√

−

1

Thus  

x

=

±

i

in addition to 3 and -3.

4 0
3 years ago
Read 2 more answers
52.3 is what percent of 1046​
satela [25.4K]

Answer:

https://www.percentagecal.com/answer/52.3-is-what-percent-of-%20%201046

Step-by-step explanation:

This will help you calculate any future percentages.

8 0
3 years ago
Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)
DiKsa [7]

Answer:

C

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. y'=(3\sin x)'=3\cos x. Differentiate again to get y''=(3\cos x)'=-3\sin x, then y''+y=-3\sin x+3\sin x=0\neq 3\sin x so this choice of y doesn't solve the equation.

B. y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x and y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x, then y''+y=10\sin x+6\cos x\neq 3\sin x so y is not a solution

C. y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x hence y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x. Then y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x so y is a solution.

D.y'=-3\sin x and y''=-3\cos x, then y''+y=0 thus y isn't a solution

E. y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x hence y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x. Then y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x then y is not a solution.

3 0
3 years ago
A circle has an area of 1075.21 m^2 <br> What is the radius to the nearest 1 decimal x.x
Sindrei [870]
Area of circle = πr²

1075.21 = πr²

1075.21/π = r²

r = √1075.21/π

r = 18.5
7 0
3 years ago
The point (1,1) is the image under the image under rhe translation (x,y) (x+3,y-3)
Dmitry_Shevchenko [17]
Sent a picture of the solution to the problem (s). I took a guess at what it asked.

4 0
3 years ago
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