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2 years ago

I’m not sure what it could be?

Mathematics

1 answer:

Soloha48 [4]2 years ago

7 0

Answer:

Step-by-step explanation:

If x equals 1/4 then it must be B because:

All the sections are divided into fourths so 1/4 plus 3/4 is 1.

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The stopping distance d of an automobile is directly proportional to the square of its speed s. On one road, a car requires 75 f

Anton [14]

Answer:

The car requires 192 feet to stop from a speed of 48 miles per hour on the same road

Step-by-step explanation:

Direct proportion means that two quantities increase or decrease in the same ratio

If y is directly proportional to x (y ∝ x) , then $\frac{y_{1}}{y_{2}}=\frac{x_{1}}{x_{2}}$ <em>OR</em> y = k x, where k is the constant of proportionality

∵ The stopping distance d of an automobile is directly

proportional to the square of its speed s

- That means d ∝ s²

∴ $\frac{d_{1}}{d_{2}}=\frac{(s_{1})^{2}}{(s_{2})^{2}}$

∵ A car requires 75 feet to stop from a speed of 30 miles per hour

∴ d = 75 feet

∴ s = 30 miles/hour

- Change the mile to feet

∵ 1 mile = 5280 feet

∴ 30 miles/hour = 30 × 5280 = 158400 feet/hour

∵ The car require to stop from a speed of 48 miles per hour

on the same road

- Change the mile to feet

∴ 48 miles/hour = 48 × 5280 = 253440 feet/hour

∵ $\frac{d_{1}}{d_{2}}=\frac{(s_{1})^{2}}{(s_{2})^{2}}$

- Substitute the values of $d_{1}$ by 75 feet, $s_{1}$ by 158400 feet/hour

and $s_{2}$ by 253440 feet/hour

∴ $\frac{75}{d_{2}}=\frac{(158400)^{2}}{(253440)^{2}}$

∴ $\frac{75}{d_{2}}=\frac{25}{64}$

- By using cross multiplication

∴ 25 × $d_{2}$ = 75 × 64

- Divide both sides by 25

∴ $d_{2}$ = 192 feet

The car requires 192 feet to stop from a speed of 48 miles per hour on the same road

4 0

2 years ago

99 % of the trees in our neighborhood are eucalyptus trees. The town planning commission wants to get rid of some of these trees

Brut [27]

Answer:

50%

Step-by-step explanation:

Let the total number of trees be T and suppose that this is made up of eucalyptus trees E and other kinds of trees, O.

Then E+O=T, and since 99% of the trees are eucalyptus trees, EE+O=0.99.

Therefore

0.99E+0.99O=E

0.01E=0.99O

E=99O.

Suppose we reduce the number of eucalyptus trees by some amount x and that the remaining number of eucalyptus trees are now 98% of the total trees.

Then we would have E−x(E−x)+O=0.98.

Therefore,

0.02(E−x)=0.98O

0.02E−0.02x=0.98O

0.02x=0.02E−0.98O

x=E−50(0.98)O

x=E−49O

x=E−49(E99)

x=5099E≈0.505050...×E.

So we end up removing a little over half of the eucalyptus trees. EDIT: Forgot to mention - removing 50.505050...% of the eucalyptus trees means that we are removing 0.50505050....×0.99T which is 0.5T or half the trees in the neighborhood.

3 0

3 years ago

Jackie cut a piece of paper along its diagonal, as shown below, forming two triangles.

harina [27]

Answer:

B. The two dimensions are the same in the triangles as they were in the rectangle.

Step-by-step explanation:

Given

Initial Shape: Rectangle (Before cut)

Final Shape: Triangles (After cut)

<em>Note that this can be explained properly with the use of attachments</em>

See attachment 1 for Before Cut