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vladimir2022 [97]
2 years ago
11

NO LINKS!! Explain your answers (show the support by showing the changes in x and y on your table). If the relationship is linea

r, inverse, or exponential, write the equation.
#5 and #6​

Mathematics
1 answer:
sdas [7]2 years ago
5 0

Answer:

<u>Linear relationship</u>: increasing or decreasing one variable will cause a corresponding increase or decrease in the other variable.

<u>Inverse relationship</u>:  the value of one variable decreases as the value of the other variable increases.

<u>Exponential relationship</u>: a constant change in the independent variable (x) gives the same proportional change in the dependent variable (y)

<u>Question 5</u>

As the x-value increases (by one unit), the y-value decreases.

Therefore, this is an inverse relationship.

The y-values are calculated by dividing 35 by the x-value.

\sf y=\dfrac{35}{x}

**I believe there is a typing error in the table and that the y-value of x = 3 should be 11.67**

<u>Question 6</u>

As the x-value increases, the y-value increases.  The y-value increases by a factor of 5 for each x-value increase of 1 unit.

Therefore, this is an exponential relationship.

\sf y=5^x

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Answer: 2*99

Step-by-step explanation:

To see if the answer is correct divide 198/99 and you'll get 2. To find answers like these you have to divide in order to get the answer that is correct.

Hope This Helps!

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Step-by-step explanation:

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All the cubes root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%20%2B%20i%7D%20" id="TexFormula1" title=" \sqrt{3 + i
melisa1 [442]

If you're looking for the cube roots of √(3 + <em>i </em>), you first have to decide what you mean by the square root √(…), since 3 + <em>i</em> is complex and therefore √(3 + <em>i </em>) is multi-valued. There are 2 choices, but I'll stick with 1 of them.

First write 3 + <em>i</em> in polar form:

3 + <em>i</em> = √(3² + 1²) exp(<em>i</em> arctan(1/3)) = √10 exp(<em>i</em> arctan(1/3))

Then the 2 possible square roots are

• √(3 + <em>i</em> ) = ∜10 exp(<em>i</em> arctan(1/3)/2)

• √(3 + <em>i</em> ) = ∜10 exp(<em>i</em> (arctan(1/3)/2 + <em>π</em>))

and I'll take the one with the smaller argument,

√(3 + <em>i</em> ) = ∜10 exp(<em>i</em> arctan(1/3)/2)

Then the 3 cube roots of √(3 + <em>i</em> ) are

• ∛(√(3 + <em>i</em> )) = ¹²√10 exp(<em>i</em> arctan(1/3)/6)

• ∛(√(3 + <em>i</em> )) = ¹²√10 exp(<em>i</em> (arctan(1/3)/6 + <em>π</em>/3))

• ∛(√(3 + <em>i</em> )) = ¹²√10 exp(<em>i</em> (arctan(1/3)/6 + 2<em>π</em>/3))

On the off-chance you meant to ask about the cube roots of 3 + <em>i</em>, and not √(3 + <em>i </em>), then these would be

• ∛(3 + <em>i</em> ) = ⁶√10 exp(<em>i</em> arctan(1/3)/3)

• ∛(3 + <em>i</em> ) = ⁶√10 exp(<em>i</em> (arctan(1/3)/3 + 2<em>π</em>/3))

• ∛(3 + <em>i</em> ) = ⁶√10 exp(<em>i</em> (arctan(1/3)/6 + 4<em>π</em>/3))

3 0
2 years ago
What triangle measure 47 68 and 65
Gwar [14]
It’s an acute scalene triangle
7 0
3 years ago
Isabel stacked two wooden blocks as shown. What is the total volume of the stacked blocks?
Kobotan [32]

9514 1404 393

Answer:

  156 cm³

Step-by-step explanation:

The volume of any prism is the product of the base area and the height of the prism. Here, we can take the "base" to be the front face of the assembly, and its "height" to be the 3 cm distance between the front and back faces.

The front face area is the sum of the triangle area and the rectangle area.

  A = 1/2bh + LW

  A = (1/2)(10 cm)(4 cm) + (16 cm)(2 cm) = 52 cm²

Then the volume is ...

  V = Bh = (52 cm²)(3 cm) = 156 cm³ . . . . total volume of the two blocks

8 0
2 years ago
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