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Pavlova-9 [17]
3 years ago
9

Which system of inequalities does the graph represent?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:system of linear equalities in one variable .

Step-by-step explanation:

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I think it’s always cause how can something that’s false be sometimes false or never false
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A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma
White raven [17]

Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

F={9, 10, 11, 12, 13}​

G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}​

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}​

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

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3 years ago
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Find the sum by first finding the equivalent fractions so both of the fractions have common
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Answer:

3x3/8x2 = 9/16

9/16+7/16 = 16/16

               =1

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7. Beyunka has six baseballs that she keeps at her grandparents' house. That
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The answer I believe is 30
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3 years ago
Help me please for the brainliest answer
AveGali [126]

Answer with Step-by-step explanation:

a) {n}^{2}  + 3 \\  \\ n = 1 \\  {1}^{2}  + 3 \\ 1 + 3 \\  = 4 \\  \\ n = 2 \\  {2}^{2}  + 3 \\ 4 + 3 \\  = 7 \\  \\ n = 3 \\  {3}^{2}  + 3 \\ 9 + 3 \\  = 12 \\  \\ n = 4 \\  {4}^{2}  + 3 \\ 16 + 3 \\  = 19 \\  \\ n = 10 \\  {10}^{2}  + 3 \\ 100 + 3  \\  = 103

In this sequence,

1st term = 4

2nd term = 7

3rd term = 12

4th term = 19

10th term = 103

b)2 {n}^{2}  \\  \\ n = 1 \\ 2 \times  {1}^{2}  \\ 2 \times 1 \\  = 2 \\  \\ n = 2 \\ 2 \times  {2}^{2}  \\ 2 \times 4 \\  = 8 \\  \\ n = 3 \\ 2 \times  {3}^{2}  \\ 2 \times 9 \\  = 18 \\  \\ n = 4 \\ 2 \times  {4}^{2}  \\ 2 \times 16 \\ =   32 \\  \\ n = 10 \\ 2 \times  {10}^{2}  \\ 2 \times 100 \\  = 200

in this sequence,

1st term = 2

2nd term =8

3rd term = 18

4th term =32

10th term = 200

4 0
3 years ago
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