You could 3•2 because your it two times =6 than it’s 2\6 make more smaller 1/3 it will be. Than you get .3333 repeating
<span>The probability that all three children will be girls is 1/3 because 3 are about to be born</span>
Answer:
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<em>1</em><em>1</em><em>y</em><em>+</em><em>1</em><em>6</em></h2>
<em>Solution</em><em>,</em>
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<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.
Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.
3(23) really means 3*23, or just 3 multiplied by 23. For example: "Jana has 23 dollars. Her friend John has $23, and his friend Jacob also has 23 dollars. How much money do they have all together?" To solve this problem mentally, you could break 3*23 into two numbers you're familiar with multiplying, like 20 and 3, and then add the numbers together. For example: 3*20 + 3*3. 3*20=60, 3*3=9, and 60+9=69. So, 3*23=69.
