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Darya [45]
3 years ago
11

Please help!! WILL GIVE BRAINLIEST

Mathematics
1 answer:
yuradex [85]3 years ago
3 0
50 ounces of chocolate is needed for the recipe
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By using (17,-13) (17,8) what is the slope
uysha [10]
Y2-y1/x2-x1

8-[-13]/17-17

21/0

this is called undefined because its denominator is zero.
4 0
3 years ago
I don't understand how to solve this, please help!
murzikaleks [220]

Answer:

x+1 , x<-1

x²-bx-4  , -1≤x≤4

1/2 x +a

substitute x=-1 , continuous everywhere

x+1=x²-bx-4 when x=-1

-1+1=-1²-b-4

<h2>1+b-4=0 ⇒ +b-3 ⇒ b=3</h2>

then for :

x²-bx-4=1/2 x +a for x=4

4²-4b-4=1/2x+a

16-4(3)-4=4/2+a

16-12-4-2=a

<h2>a=-2</h2>

the equations will be :

x+1

x²-3x-4

1/2x-2

I hope this help

7 0
3 years ago
What is the slope of the line?
meriva
The slope of the line can be defined as y = mx + b, where m is the slope
To find the slope, one will need to use the expression Δy/Δx (y final - y initial)/(x final - x initial)
For this problem, that equals 1/3

Now we will use the point slope form
(y - y initial) = m (x - x initial):

y + 1 = 1/3 (x - 2)

y = 1/3x - 5/3
7 0
2 years ago
Select all the correct answers. Which two inequalities can be used to find the solution to this absolute value inequality? 3|x +
ziro4ka [17]

The absolute value inequality can be decomposed into two simpler ones.

x < 0

x > -8

<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

x + 4 > - 4

Solving both of these we get:

x < 4 - 4

x > -4 - 4

x < 0

x > -8

These are the two inequalities.

Learn more about inequalities:

brainly.com/question/24372553

#SPJ1

6 0
11 months ago
X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} &#10;y= \frac{3*5}{2} &#10;y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
5 0
3 years ago
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