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kiruha [24]
3 years ago
12

How is this proportional?

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

you are subtracting 1.40 everytime to get the number at the bottom

Step-by-step explanation:

2 - 1.40 = 1.40

3 - 1.40 = 2.40

6 - 1.40 = 5.40

7 - 1.40 = 6.40

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Vilka [71]

-7/10 divided by 2/5 is -35/20 or -7/4 in the simplest form

-1/4 times (-4/3) is 4/12 or 1/3 in the simplest form

-3 1/3 or -10/3 times by -2 7/10 or -27/10 is 270/30 or 9

-10 2/7 or -72/7 divided by -4 4/11 or -48/11 is 792/336 or 33/14 in the simplest from

5 0
3 years ago
Plant A is 18 inches tall after one week 36 inches tall after two weeks 56 inches tall after three weeks Plan B is 18 inches tal
KATRIN_1 [288]
So what is your question
8 0
4 years ago
The newly elected president needs to decide the remaining 5 spots available in the cabinet he/she is appointing. If there are 15
skad [1K]

Answer: There are 360360 ways to appoint the members of the cabinet.

Step-by-step explanation:

Since we have given that

Number of eligible candidates = 15

Number of spots available = 5

We need to find the number of different ways the members can be appointed where rank matters

For this we will use "Permutations":

So, the required number of different ways in choosing the members for appointment is given by

^{15}P_5=360360

Hence, there are 360360 ways to appoint the members of the cabinet.

7 0
3 years ago
Someone hmu I’m bored<br><br> Also what’s 2+2
bulgar [2K]

Answer:4

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5 0
4 years ago
Read 2 more answers
A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The
disa [49]

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ±  5.09

=-2.09, 8.09  is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

5 0
3 years ago
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