1. A in some part is correct, but the triangles are indeed correct, and the argument is for HL, so the answer is C
2. Are congruent by SSS (both shares a side).
Answer:
Step-by-step explanation:
Sounds as tho' possible answer choices were listed. Please, share them without being asked to do so. Thank you.
7√(x²) 7√(x²)
------------- = ----------------------
5 √(y³) 5√( y^(3/2) )
We want to get the fractional exponent out of the denominator. To do this, multiply both numerator and denominator by y^(1/2):
7√(x²) 7√(x²) y^(1/2) 7√(x²)·y^(1/2) 7x√y
------------- = --------------------- * ----------- = --------------------- = ----------
5 √(y³) 5√( y^(3/2) ) y^(1/2) 5 √(y²) 5y
This is the final answer. We have succeeded in removing radicals / fractional exponents from the denominator.
Answer: The distance between the girls is 362.8 meters.
Step-by-step explanation:
So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.
The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:
Tan(A) = opposite cath/adjacent cath.
Tan(40°) = X/160m
Tan(40°)*160m = 134.3 m
Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°
So we have:
Tan(55°) = X/160m
Tan(55°)*160m = X = 228.5 m
And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:
Dist = 228.5m + 134.3m = 362.8m
If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.
d^2=x^2+x^2
d^2=2x^2
d=√(2x^2)
Since d=2r, r=d/2 so
r=(1/2)√(2x^2)
r=√((2x^2)/4)
r=√(x^2/2), since x=8
r=√(64/2)
r=√32
r=√(16*2)
r=4√2 in (exact)
r≈5.66 in (to nearest hundredth of an inch)
Increase = Going up.
Therefore Graph D is increasing. simply logic
