Seriously: add the x's divide by 2, add the y's divide by 2, bob's your uncle. you have the midpoint.
Answer:
(-1.92, 1.08)
Step-by-step explanation:
The <em>incenter</em> is the center of the largest circle that can be inscribed in the triangle. That circle is called the <em>incircle</em>. The incenter is at the point of intersection of the angle bisectors. For a right triangle, the <em>inradius</em> (the radius of the incircle), is found from a simple formula:
r = (a + b - c)/2 . . . . . where c is the hypotenuse, and a and b are the legs
In your triangle, the inradius is ...
r = (5 + 3 -√(5² +3²))/2 = 4 -√8.5 ≈ 1.08452
Among other things, this means the coordinates of the incenter are about (1.08, 1.08) from the right angle vertex, so are about ...
incenter ≈ (-1.92, 1.08)
I would subtract the 2nd from the first one
so -4x - -2x = -2x
4y - 4y = 0
-20 - -2 = -18
-2x = -18
now I would divide that by -2 to get the value for x
so no we have x = 9
now you just have to substitute that into one of the equations and simplify to get y
-2 X 9 + 4y = -2
-18 + 4y = -2
4y =16
y = 4
Answer:
See below.
Step-by-step explanation:
1) Please check the number of volume of steel. It should be 54,259.2
![{cm}^{3}](https://tex.z-dn.net/?f=%20%7Bcm%7D%5E%7B3%7D%20)
. Not 54,259.2 cm. Right?
2) If so,
First
The volume of single rod
![= \pi \times ( { \frac{4}{2} })^{2} \times 60= \pi \times {2}^{2} \times 60= 4\pi \times 60= 4 \times 3.14 \times 60= 753.6 {cm}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cpi%20%5Ctimes%20%28%20%7B%20%5Cfrac%7B4%7D%7B2%7D%20%7D%29%5E%7B2%7D%20%5Ctimes%2060%3D%20%5Cpi%20%5Ctimes%20%20%7B2%7D%5E%7B2%7D%20%5Ctimes%2060%3D%204%5Cpi%20%5Ctimes%2060%3D%204%20%5Ctimes%203.14%20%5Ctimes%2060%3D%20753.6%20%7Bcm%7D%5E%7B3%7D%20)
The number of rods
![= \frac{54259.2}{753.6} = 72](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B54259.2%7D%7B753.6%7D%20%20%3D%2072)