Step-by-step explanation:
anyway, without any further information about ground consistency, friction and stuff, we have to assume ideal circumstances.
so, the same energy that made the ball flying through the air makes it also bounce or roll across the ground carrying it exactly the same distance at the same time.
the distances with an ideal, reflective ground will be the same.
it is the same energy released with the same inertia.
Answer:
We reject H₀. We accept Hₐ (the cream can improve the the skin of more than 50%
Step-by-step explanation:
We have a proportion one tail test (right)
P₀ = 50 % = 0,5
P = 44/53 = 0.831
sample size = n = 53
Confidence interval = 0,95 α = 0.05 then z(c) = 1.64
1.-Hypothesis
H₀ null hypothesis P₀ = 0.5
Hₐ alternative hypothesis P₀ > 0.5
2.-Compute z(s)
z(s) = ( P - P₀ ) / √P₀Q₀/n ⇒ z(s) = (0.831 - 0.5 )/√0.5*0.5/53
z(s) = 0.3301/0.06
z(s) = 5.5
3.-Compare z(c) and z(s)
z(s) > z(c) 5.5 > 1.64
therefore z(s) is in the rejection region we reject H₀ . And accept Hₐ
9514 1404 393
Answer:
y = 3/4x -7/4 or y = 0.75x -1.75
Step-by-step explanation:
The two point form of the equation of a line is useful when you are given 2 points and asked for the equation.
y = (y2 -y1)/(x2 -x1)·(x -x1) +y1
y = (35 -14)/(49 -21)·(x -21) +14 . . . . . . fill in given points
y = 21/28(x -21) +14 . . . . . . . . . . . . . . . simplify a bit
y = 3/4(x -21) +14 . . . . . . . . . . . reduce the fraction
y = 3/4x -15 3/4 +14 . . . . . . . .eliminate parentheses
y = 3/4x -7/4 or y = 0.75x -1.75
Substituting our values into the formula we get