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3 years ago

Does anyone know the answer ?

Mathematics

2 answers:

Alecsey [184]3 years ago

5 0

Answer:

As I’m unsure as to whether or not this is a joke or not, I’ll say 15 cm.

ycow [4]3 years ago

3 0

It’s 15cm for the answer

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EXAMPLE 2 Find a formula for the general term of the sequence 3 5 , − 4 25 , 5 125 , − 6 625 , 7 3125 , assuming that the patter

g100num [7]

Answer:

$a_n=\dfrac{(2+n)\cdot(-1)^{n + 1}}{5^n}$

Step-by-step explanation:

We are to find a formula for the general term of the sequence

$\dfrac{3}{5}, -\dfrac{4}{25}, \dfrac{5}{125}, -\dfrac{6}{625}, \dfrac{7}{3125}$

We are given that $a_1=\dfrac{3}{5}, a_2=-\dfrac{4}{25}, a_3=\dfrac{5}{125}, a_4=-\dfrac{6}{625}, a_5=\dfrac{7}{3125}$ .

The numerators of these fractions start with 3 and increase by 1. The second term has numerator 4, the third term has numerator 5; in general, the nth term will have numerator 2+n

The denominators are powers of 5, so $a_n$ has denominator $5^n$
The signs of the terms are alternately positive and negative so we need to multiply by a power of −1. Here we want to start with a positive term and so we use $(-1)^{n + 1}$ .

Therefore,

$a_n=\dfrac{(2+n)\cdot(-1)^{n + 1}}{5^n}$

5 0

3 years ago

Suppose that 19 inches of wire costs 57 cents.

Setler [38]

Answer:

48 cents

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

May I please get help

Zielflug [23.3K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS QUESTION!!

marin [14]

Answer:

+$90;

$1,600

Step-by-step explanation:

The equation, $y = 1600 + 90x$ , given to us tells us much about the situation described above.

y = total pay

x = number of copies of Math is fun

1600 = y-intercept, that is the starting value or the pay he gets only if Sam sold 0 copy of Math is fun. That is, when x = 0, y = 1,600.

90 = unit rate or the change in the total pay for each copy of Math is fun that Sam sells.

Therefore, our answers would be:

+$90, and $1,600

5 0

3 years ago

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago