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Harman [31]
3 years ago
12

Sandy recently made a 210-mile car trip, starting from home at noon. The graph at right shows how Sandy’s distance from home (me

asured in miles) depends on the number of hours after noon. Make up a story that accounts for the four distinct parts of the graph. In particular, identify the speed at which Sandy spent most of the afternoon driving.
​

Mathematics
1 answer:
vichka [17]3 years ago
5 0

There is no one set answer as you could get creative to have multiple variations; however, they should all have the same key features.

One such story could be this:

Sandy starts driving at noon and her average speed is 30 mph. After 1 hour, she realizes that she may not make it in time, so she increases her speed to 60 mph. Or perhaps that traffic lightened up to allow her to drive faster. By 2 PM, she stops for gas and food. She also decides to rest for an hour. At 3 PM is when she starts driving again, and does so at an average speed of 60 mph like the second leg of the trip. She finally arrives at her destination at 5 PM, which is 5 hours after she started.

Sandy spent the most time driving <u>60 mph</u> which consists of the second and fourth parts of the trip. If you ignore the rest period, then it would be the second and third driving parts of the trip.

---------------------

If you're wondering how I got the speed values, I used the slope formula

m = (y2-y1)/(x2-x1)

So for instance, the slope through (0,0) and (1,30) is

m = (y2-y1)/(x2-x1)

m = (30-0)/(1-0)

m = 30

Showing the first leg of the trip she had an average speed of 30 mph.

The flat part of the graph has slope 0 to indicate that Sandy isn't driving at all during that period (since her mileage y value isn't going up).

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   ^ This is the tenths place.

Look at the number after it, if it's 5 or more we round up, if it's 4 or less we round down.

The number is 6, so we round up to 9.7.

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Carmen wants to join a gym. Gym A costs $26.76 plus an additional $4 for each visit. Gym B has no initial fee but costs $12.92 f
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Answer:

After 3 visits both plans will cost the same.

Step-by-step explanation:

Gym A costs $26.76 plus an additional $4 for each visit.

Gym B has no initial fee but costs $12.92 for each visist.

The cost for gym A can be written as

C= $26.76 + 4(x)  where x is the number of visits to the gym A

The cost for gym B can be written as

C= $12.92 (x)  where x is the number of visits to the gym B

Both costs will be equal

12.92x= 26.76 +4x

12.92x-4x= 26.76

8.92x= 26.76

x= 26.76/8.92

x= 3

after 3 visits both plans will cost the same.

Check

12.92x= 26.76 +4x

12.92*3= 26.76 +12

38.76= 38.76

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The seaport city that was the scene of thousands of Allied troops being rescued by boats was called _____.
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Si el máximo común divisor (MCD) de 6432 y 132 disminuye en 8, entonces será igual a: * 1 punto 6 4 -2 -6
swat32

Answer:

4

Step-by-step explanation:

Para empezar el maximo común divisor (MCD) de dos números se refiere al número en común que tienen ambos números, entre los cuales pueden ser divididos. En el caso del máximo se refiere al número más alto posible en que ambos números pueden ser divididos.

Para poder saber esto, es necesario anotar los factores en los cuales pueden ser divididos ambos números. Sin embargo, ya que son cantidades altas, puede tomar mucho tiempo determinar esto, por lo tanto nos vamos a la respuesta final.

Sabemos que el MCD de 132 y 6432 es disminuido en 8 unidades, es decir, se le resta 8 al MCD de esos números, y ese número debe coincidir con alguna de las opciones puesta ahí. Por lo tanto, lo que vamos a hacer para resolverlo rápidamente es sumarle 8 a cada una de las opciones y luego, verificaremos si el número obtenido es divisor de 132 y 6432.

<u>Obtención del MCD original:</u>

a) 6 + 8 = 14

b) 4 + 8 = 12

c) 2 + 8 = 6

d) 6 + 8 = 2

Con estos resultados, veamos cual de ellos es el MCD de 132 y 6432.

<u>Para el 6432:</u>

6432 / 2 = 3216

6432 / 6 = 1072

6432 / 12 = 536

6432 / 14 = 459,24

Podemos observar con estos resultados que el 14 queda descartado al tener un resultado decimal, por lo tanto debe ser 2, 6 o 12. Veamos la cuenta con el 132:

<u>Para el 132:</u>

132 / 2 = 66

132 / 6 = 22

132 / 12 = 11

Podemos observar ahora en este caso que el 132 es divisible entre 12, por lo tanto, es el MCD entre 132 y 6432, asi que se concluye que el resultado de disminuir por 8 el MCD de ambos números es:

<h2>12 - 8 = 4</h2>

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