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fgiga [73]
3 years ago
15

Jim is a minor manufacturer. He needs to know the forecasted sales for September to formulate a plan in advance. What is his for

ecasted sale using simple average
method?
Month Sales ($)
January 3,000
February 3,500
March 4,000
April 4,500
May 3,000
June 3,500
July 4,204
August 5,000
Mathematics
1 answer:
Olin [163]3 years ago
3 0

Answer:

  $3838

Step-by-step explanation:

The mean of the given numbers is their sum divided by the number of them:

  mean = (3000 +3500 +4000 +4500 +3000 +3500 +4204 +5000)/8

  = 30704/8 = 3838

If Jim is using this mean for his forecast, then his forecasted sales is $3838.

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Find the distance between the lines<br> Y=3x+10<br> Y=3x-20<br> AND <br> Y=3/2x+3/2<br> Y=3/2x-5
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At first we need to know how to find the distance between two parallel lines
The parallel lines which have the same slope 
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So, the distance between y₁ and y₂ = d = \frac{|c_{1} - c_{2}|}{\sqrt{1 + m^{2}}}
========================================================

Part (1):
=======

<span>The distance between the lines
</span>
<span> Y₁ = 3x + 10    and       Y₂ = 3x - 20</span>
∴ m = 3  , c₁ = 10  and  c₂ = -20
∴ d = \frac{| 10 - (-20)|}{\sqrt{1 + 3^{2}}}= \framebox{9.5}

========================================================

Part (2):
=======

<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span>    and       Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5  , c₁ = 3/2 = 1.5   and  c₂ = -5
∴ d = \frac{| 1.5- (-5)|}{\sqrt{1 + 1.5^{2}}}= \framebox{3.6}

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