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2 years ago

Which table represents a linear function? Plz answer quickly!!! Thank you! :)

Mathematics

1 answer:

Luda [366]2 years ago

4 0

Answer:

The first one

Step-by-step explanation:

You can see the pattern

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if <img src="https://tex.z-dn.net/?f=h%28x%29%3D4x%5E%7B2%7D%20-16" id="TexFormula1" title="h(x)=4x^{2} -16" alt="h(x)=4x^{2} -1

Elan Coil [88]

Answer: h(x) = (2x - 14)^2 - 19

This will take the vertex from (0,-16), the original equation, to (7,-19), the new equation. This demonstrates the x-value increasing by 7, moving right on the coordinate plane, as well as the y-value decreasing by -3, going down on the coordinate plane.

6 0

2 years ago

Write a polynomial that represents the length of the rectangle help please !!

disa [49]

Answer:

$\textsf{Length}=0.8x^2-0.7x+0.7\quad \sf units$

Step-by-step explanation:

Area of a rectangle = width × length

Therefore, to find the length of the rectangle, we need to divide the area by the width.

Using long division:

$\large\begin{array}{r}0.8x^2-0.7x+0.7\phantom{)} \\x+0.5{\overline{\smash{\big)}\,0.8x^3-0.3x^2+0.35x+0.35\phantom{)}}}\\-~\phantom{(}\underline{(0.8x^3+0.4x^2)\phantom{-b))))))))))))))}}\\0-0.7x^2+0.35x+0.35\phantom{)}\\ \underline{-~\phantom{()}(-0.7x^2-0.35x)\phantom{-b)))))}}\\ 0.7x+0.35\phantom{)}\\\underline{-~\phantom{()}(0.7x-0.35)}\\ 0\phantom{)}\end{array}$

Therefore, the length of the rectangle is:

$0.8x^2-0.7x+0.7$

5 0

1 year ago

Find two numbers the quotiens is between 136÷6

Alekssandra [29.7K]

The answer is 22.6 so the quotient would be between 22.0 and 23.0, hope this helps.

6 0

3 years ago

PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Brums [2.3K]

The given matrix equation is,

$1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]$ .

Multiplying the matrices with the scalars, the given equation becomes,

$\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Adding the matrices,

$\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Matrix equality gives,

$1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2$

Solving the equations together,

$y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10$

We can see that the equations are not consistent.

There is no solution.

3 0

2 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

2 years ago