Answer:
dV = - 5.73*10⁹ m³/s
Step-by-step explanation:
Question: What is the rate of change of the volume of the prism at that instant (in cubic meters per second) ?
A function can be dependent on one or more variables. The change in the function due to a change in one o its variables is given by the functions derivative with respect to that variable. For functions that are composed of products of its variables, we may use the product rule to determine its derivative.
The volume of a square prism with base a and height h is given by
V = a²h
When the base and height are changing, we have
dV = 2ah(da/dt) + a²(dh/dt)
Given
a = 4 Km
h = 9 Km
da/dt = - 7 Km/min
dh/dt = 10 Km/min
we have
dV = 2(4 Km)(9 Km)(- 7 Km/min) + (4 Km)²(10 Km/min)
⇒ dV = - 504 Km³/min + 160 Km³/min = - 344 Km³/min
⇒ dV = - 5.73*10⁹ m³/s
Consider the following formula to find the circumference of circle
C= 2^_r
here r is radius of circle
the radius of circular is 25 ft.
Therefore circumference is as follows
C = 2^_r
= 2 × 3.14 (25)
= 157.
circumference of circle feet is 157 × 12 inches.
Solve equation for y.
5x - y = 3
-y = -5x + 3
y = (-5x + 3)/(-1)
y = 5x - 3
The slope for this equation is 5.
The slope of the equation we want is the negative reciprocal of 5.
Let m = slope of equation we want.
m = -1/5
We are given the point (10,4).
Plug both into the point-slope formula.
y - 4 = (-1/5)(x - 10)
y - 4 = (-1/5)x + 2
y = (-1/5)x + 2 + 4
The equation we want is
y = (-1/5)x + 6
Did you follow?
.2 converted to a fraction would be 1/5
The range is the high and low points.
So (5, 2]
