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s2008m [1.1K]
2 years ago
9

The following distribution is not a probability distribution because

Mathematics
1 answer:
olasank [31]2 years ago
4 0

Answer:

C The probability values do not add to 1

Step-by-step explanation:

Given

The above table

Required

Why is it not a probability distribution

In probability, the sum of all probabilities must equal 0.

But in this case:

\sum P(x) \ne 0

Because:

0.08 + 0.23 + 0.44 + 0.12 + 0.24 \ne 0

1.11 \ne 0

Hence:

Option (c) answers this question

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SteIf -11 + N = -11 then N is the additive inverse because if we do process of elimination (POE) we can cross out C and D because this is a addition problem not a multiplication, and we know its not B because that's like 99 + 0 = 99 set, but instead its A because its just like  -8 + 8 = 0. (If this was not a multiple choice question then tell me)



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5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ
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Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

<em>Let </em>\hat p<em> = sample proportion</em>

The z-score probability distribution for sample proportion is given by;

               Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

           p = population proportion = 48%

           n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } } ) = P(Z < 0.89) = 0.8133

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>

Therefore, probability that the sample proportion will be greater than 0.50 is 0.8133.

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