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krek1111 [17]
2 years ago
9

What is. m + 0.6 = 2.6

Mathematics
1 answer:
professor190 [17]2 years ago
5 0

Answer:

m=2

Step-by-step explanation:

STEP 1 : m+0.6=2.6

move constant to the right-hand side and change it's sign m=2.6-0.6

STEP 1: m=2.6-0.6

subtract the numbers m=2

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Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.
Leona [35]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: flexural strength of concrete beams.

Data:

7.3 6.8 8.6 9.7 11.6 9.7 6.8 7.7 11.8 7.4 8.1 8.7 6.3 7.9 7.0 7.9 7.8 6.5 6.3 7.0 7.5 7.7 7.2 11.3 9.0 10.7 5.1

a.

The point estimate of the mean value is the sample mean. You calculate it using the following formula:

X[bar]= ∑X/n= 219.40/27= 8.1259≅ 8.13

b)x

b.

The point estimate that divides the sample in 50%-50% is the measure of central tendency called Median(Me).

To reach the median you have to calculate it's position (PosMe)

For uneven samples PosMe= (n+1)/2= (27+1)/2= 14 ⇒ This means that the Median is the 14th observation of the data set.

So next is to order the data from lower to heighest and identify the value in the 14th position:

5,1 ; 6,3; 6,3; 6,5 ; 6,8; 6,8; 7; 7; 7,2; 7,3; 7,4 ; 7,5 ; 7,7 ; 7,7 ; 7,8 ; 7,9 ; 7,9 ; 8,1 ; 8,6 ; 8,7 ; 9 ; 9,7 ; 9,7 ; 10,7 ; 11,3 ; 11,6 ; 11,8

Me= 7.7

d) x tilde

c.

The point estimate of the population standard deviation is the sample standard deviation. The standard deviation is the square root of the variance, so the first step is to calculate the sample variance:

S^2= \frac{1}{n-1}*[sumX^2-\frac{(sumX)^2}{n} ]

∑X²= 1858.92

S^2= \frac{1}{26}*[1858.92-\frac{219.40^2}{27} ] = 2.926

S= √2.926= 1.71

The standard deviation is a measurement of variability, it shows how to disperse the data is concerning the sample mean.

d. This estimate describes the spread of the data.

I hope it helps!

7 0
3 years ago
A soccer team is having a car wash. The team spent $50 on supplies. They earned $300, including tips. The team's profit is the a
Amiraneli [1.4K]
  • Money earned =$300
  • Money spent on supllies=$50

Profit =Money left after supplies

\\ \sf\longmapsto Profit=300-50

\\ \sf\longmapsto Profit=\$250

7 0
3 years ago
Read 2 more answers
Evaluate the expression: -(8 - 12) + 6° + (-4)2.
serg [7]

Answer:

-4 + 6°

Step-by-step explanation:

- (8 - 12) + 6° + (- 4)2 = - ( - 4) + 6° - 8 = 4 + 6° - 8 = - 4 + 6°

8 0
3 years ago
Look at the data set below:
Elenna [48]
Median: Sort from least to greatest and find the # in the middle.
Sort: 54, 58, 58, 60, 62. 
Number in the middle: 58, so the median is 58.
Mode: 58, because it appears most. 
Range: Subtracting bigger number from smaller number.
Finding it: 62-54 = 8
If you want to find the mean, then here:
Mean: Solving average (adding all #s together and dividing by how many numbers are there) <span>58 + 54 + 62 + 58 + 60 = 292.
</span>Divide by 5 = 58.4
Hope that helps you. Good luck with it.
Follow if you want.
6 0
3 years ago
Read 2 more answers
The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management
dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1=  13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the  number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting  X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12  in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2  ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0
3 years ago
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