1. Assume the manufacturer produced 100 products.
2. 70 are acceptable and 30 are defective.
3. the first product has a probability of 70/100 to be selected from the acceptable ones. The second 69/99 (one is removed from the good ones) and the third one 68/98
4. so P(pick 3 consecutive acceptable products)=

=0.339
5. If familiar to the Combination formula C(n, r)=

:
P(picking 3 acceptable out of 100)=n(picking 3 acceptable)/n(picking 3)=C(70, 3)/C(100/3)=

= 0.339
The cost of each duck is $ 7 and cost of each chicken is $ 12.
Step-by-step explanation:
Given,
5 chickens and 3 ducks are bought by $ 81
A chicken costs $ 5 more than a duck.
To find the cost of each duck and cost of each chicken.
Let,
The cost of each duck = x
The cost of each chicken = x+5
According to the problem,
5(x+5)+3x = 81
or, 5x+25+3x = 81
or, 8x = 81-25
or, 8x = 56
or, x = 7
Hence,
The cost of each duck = $ 7
The cost of each chicken = $ 7+5 = $ 12
Step-by-step explanation:
<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>
Given monomials are 21 xy³ and 24x²y²
21 xy³ = 3×7×x×y×y×y
24x²y² = 3×8×x×x×y×y
HCF of 21xy³ and 24x²y²
=> 3×x×y×y
=> 3xy²
HCF of 21xy³ and 24x²y² = 3xy²
<h2>b)</h2>
Given monomials are 18 ab and 36abc
18 ab = 18×a×b
36abc = 2×18×a×b×c
HCF of 18 ab and 36abc
=> 18×a×b
=> 18ab
HCF of 18 ab and 36abc = 18ab
<h2>c)</h2>
Given monomials are 4p³q²r , -12pqr² and 16p²q²r²
4p³q²r = 4×p×p×p×q×q×r
-12pqr² = -3×4×p×q×r×r
16p²q²r² = 4×4×p×p×q×q×r×r
HCF of 4p³q²r , -12pqr² and 16p²q²r²
=> 4×p×q×r
=> 4pqr
HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr
<h2><u>Used Concept :-</u></h2>
→ The HCF of two or more numbers is the highest Common factor
→ The product of least common factors is the HCF of the numbers
True
Every rational number<span> can be written as a fraction a/b , where a and b are </span>integers<span>. ... If a </span>number<span> is a whole </span>number<span>, for instance, it must also be an </span>integer<span> and a </span>rational<span>.</span>
Answer:
$12.75
Step-by-step explanation:
If you multiply 4.25 by 3 then you get 12.75.