16, because all the other numbers are odd and 16 is even
Answer:
Answers:
k = 13The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Step-by-step explanation:
If this is wrong i am so sorry i tried my best.
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The formula
in solving the integral of the infinity of 3 is ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>
Substitute the numbers given
then solve
limn→inf∫3n(1/((n−2)(3/2))dn
limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)
=0+2=2
Solve for the integral of 2 when 2 is approximate to 0.
Transpose 2 from the other side to make it -2
∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C
(x−2)−1/2=1x−2−−−−√
0−(3−2)−1/2−1/2=2
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Answer:
#1- is C / #2- is b
Step-by-step explanation:
