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galina1969 [7]
3 years ago
5

Re-write the quadratic function below in Standard Form y = -9(x - 1)(x + 2)

Mathematics
2 answers:
Feliz [49]3 years ago
6 0

Answer:

-9x^2 - 9x + 18

Step-by-step explanation:

-9 • (x - 1) • (x + 2)

-9x + 9 • (x + 2)

-9x^2 -18x + 9x + 18

-9x^2 - 9x + 18

Inga [223]3 years ago
4 0

Answer:

y = - 9x² - 9x + 18

Step-by-step explanation:

y = - 9(x - 1)(x + 2) ← expand factors using FOIL

   = - 9(x² + x - 2) ← distribute parenthesis by - 9

y = - 9x² - 9x + 18 ← in standard form

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Fiesta28 [93]

Answer:

x= 45

Step-by-step explanation:

x= -15*-3

x= 45

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3 years ago
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3 years ago
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Explanation:

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2 years ago
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Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima
Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

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3 years ago
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